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MariettaO [177]
3 years ago
6

Which statements describe projectile motion? Check all that apply.

Physics
2 answers:
miv72 [106K]3 years ago
5 0

In projectile motion we can say initial components of velocity is

v_x = v_0 cos\theta

v_y = v_0 sin\theta

now here horizontal motion is uniform motion as there is no force in this direction while in vertical direction due to gravity it will accelerate

so we have

x = v_0 cos\theta * t

y = v_0 sin\theta * t - \frac{1}{2}gt^2

so here we have x and y coordinates are related to each other as it will take same time to move the positions

so here correct options are

<em>Projectile motion is a combination of horizontal and vertical motion. </em>

<em>The horizontal and vertical motions of a projectile are dependent on each other.</em>

nlexa [21]3 years ago
5 0

Answer:

C. Projectile motion is a combination of horizontal and vertical motion.

D. The horizontal and vertical motions of a projectile are independent.

Explanation:

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A 275 g block of ice at -10.0°C is released from rest on a 32.0° incline. After 7.00 s, it has
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A bird carries a 25 g oyster to a height of 11m what is the gravitational potential energy of the oyster
garik1379 [7]

Given data:

Mass of oyster (m) = 25 g,

                              = 0.025 kg            (<em> since 1 Kg = 1000 g)</em>

Height of oyster (h) = 11 m,

determine gravitational potential energy (GPE) = ?

Gravitational potential energy is energy of an object possesses because of its position on the earth. The amount of gravitational potential energy of an object on earth depends on its<em> mass</em> and<em> height </em>from the earth.  

Mathematically,

        GPE = m. g. h <em>Joules</em>

<em>         Where, </em>

<em>               </em>GPE =<em> </em>gravitational potential energy,

<em>         </em>          m = mass of object in Kg,

                  g = gravitational force in m/s²,     g = 9.8 m/s²

                  h = height of the object in meters,

     Now substituting all the values in the equation GPE

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7 0
3 years ago
a 30 kg child is sitting 2 meters from the center of a merry go round. The coefficients of static and kinetic friction between t
laiz [17]

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Mass M = 30kg

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Coefficient of kinetic friction μ = 0.6

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This force must be greater than or equal to the kinetic friction Fk. That is,

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V = 5.24 m/s

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