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MariettaO [177]
3 years ago
6

Which statements describe projectile motion? Check all that apply.

Physics
2 answers:
miv72 [106K]3 years ago
5 0

In projectile motion we can say initial components of velocity is

v_x = v_0 cos\theta

v_y = v_0 sin\theta

now here horizontal motion is uniform motion as there is no force in this direction while in vertical direction due to gravity it will accelerate

so we have

x = v_0 cos\theta * t

y = v_0 sin\theta * t - \frac{1}{2}gt^2

so here we have x and y coordinates are related to each other as it will take same time to move the positions

so here correct options are

<em>Projectile motion is a combination of horizontal and vertical motion. </em>

<em>The horizontal and vertical motions of a projectile are dependent on each other.</em>

nlexa [21]3 years ago
5 0

Answer:

C. Projectile motion is a combination of horizontal and vertical motion.

D. The horizontal and vertical motions of a projectile are independent.

Explanation:

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Rachel and Sarah are on a bus travelling at 5 mph past John who is standing on the sidewalk. Rachel then throws a ball
oksian1 [2.3K]

Answer:

I think C

Explanation:

Since the bus is moving away from John.

{C - V}.

5 0
2 years ago
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 81 N acts on
tensa zangetsu [6.8K]

Answer:

18 N

Explanation:

You have to do:

81 N: 9 ms2= x: 2 ms2

6 0
3 years ago
The lawn sprinkler consists of four arms that rotate in the horizontal plane. The diameter of each nozzle is 8 mm, and the water
sashaice [31]

Answer: the constant angular velocity of the arms is 86.1883 rad/sec

Explanation:

First we calculate the linear velocity of the single sprinkler;

Area of the nozzle = π/4 × d²

given that d = 8mm = 8 × 10⁻³

Area of the nozzle = π/4 × (8 × 10⁻³)²

A = 5.024 × 10⁻⁵ m²

Now total discharge is dived into 4 jets so discharge for single jet will be;

Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec

So using continuity equation ;

Q_single = A × V_single

V_single = Q_single/A

we substitute

V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)

V_single = 29.8566 m/s

Now resolving the forces as shown in the second image,

Vt = Vcos30°

Vt = 29.8566 × cos30°

Vt = 25.8565 m/s

Finally we calculate the angular velocity;

Vt = rω

ω_single = Vt / r

from the given diagram, radius is 300mm = 0.3m

so we substitute

ω_single = 25.8565 / 0.3

ω_single = 86.1883 rad/sec

Therefore the constant angular velocity of the arms is 86.1883 rad/sec

7 0
3 years ago
Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
netineya [11]

Answer:

Δu=1300kJ/kg  

Explanation:

Energy at the initial state

p_{1}=200kPa\\t_{1}=300^{o}\\u_{1}=2808.8kJ/kg(tableA-5)

Is saturated vapor at initial pressure we have

p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)

Process 2-3 is a constant volume process

p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

=2808.8kJ/kg-1508.6kJ/kg\\=1300kJ/kg

Δu=1300kJ/kg  

3 0
2 years ago
Why is it not necessary for radio telescope surfaces to be as smooth as a mirror?
Law Incorporation [45]
It doesn't on account of radio waves are longer than optical waves. Radio waves are a sort of electromagnetic radiation with wavelengths in the electromagnetic range longer than infrared light. These long waves are in the radio locale of the electromagnetic range.
8 0
3 years ago
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