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MariettaO [177]
3 years ago
6

Which statements describe projectile motion? Check all that apply.

Physics
2 answers:
miv72 [106K]3 years ago
5 0

In projectile motion we can say initial components of velocity is

v_x = v_0 cos\theta

v_y = v_0 sin\theta

now here horizontal motion is uniform motion as there is no force in this direction while in vertical direction due to gravity it will accelerate

so we have

x = v_0 cos\theta * t

y = v_0 sin\theta * t - \frac{1}{2}gt^2

so here we have x and y coordinates are related to each other as it will take same time to move the positions

so here correct options are

<em>Projectile motion is a combination of horizontal and vertical motion. </em>

<em>The horizontal and vertical motions of a projectile are dependent on each other.</em>

nlexa [21]3 years ago
5 0

Answer:

C. Projectile motion is a combination of horizontal and vertical motion.

D. The horizontal and vertical motions of a projectile are independent.

Explanation:

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Vsevolod [243]

0.26 there you go buddy

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2 years ago
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The radius of a planet is 2400 km, and the acceleration due to gravity at its surface is 3.6 m/s2.
kiruha [24]

Answer:

3.1\cdot10^{23}\:\mathrm{kg}

Explanation:

We can use Newton's Universal Law of Gravitation to solve this problem:

g_P=G\frac{m}{r^2}., where g_P is acceleration due to gravity at the planet's surface, G is gravitational constant 6.67\cdot 10^{-11}, m is the mass of the planet, and r is the radius of the planet.

Since acceleration due to gravity is given as m/s^2, our radius should be meters. Therefore, convert 2400 kilometers to meters:

2400\:\mathrm{km}=2,400,000\:\mathrm{m}.

Now plugging in our values, we get:

3.6=6.67\cdot10^{-11}\frac{m}{(2,400,000)^2},

Solving for m:

m=\frac{2,400,000^2\cdot3.6}{6.67\cdot 10^{-11}},\\m=\fbox{$3.1\cdot10^{23}\:\mathrm{kg}$}.

6 0
2 years ago
The index of refraction of Sophia's cornea is 1.387 and that of the aqueous fluid behind the cornea is 1.36. Light is incident f
shtirl [24]

Answer:

17.85°

Explanation:

To find the angle to the normal in which the light travels in the aqueous fluid you use the Snell's law:

n_1sin\theta_1=n_2sin\theta_2

n1: index of refraction of Sophia's cornea = 1.387

n2: index of refraction of aqueous fluid = 1.36

θ1: angle to normal in the first medium = 17.5°

θ2: angle to normal in the second medium

You solve the equation (1) for θ2, next, you replace the values of the rest of the variables:

\theta_2=sin^{-1}(\frac{n_1sin\theta_1}{n_2})\\\\\theta_2=sin^{-1}(\frac{(1.387)(sin17.5\°)}{1.36})=17.85\°

hence, the angle to normal in the aqueous medium is 17.85°

7 0
3 years ago
The relationship among mass force and acceleration is explained by
Anettt [7]
Newton's second law of motion. F = m a .
7 0
2 years ago
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Roadrunner speeds up from 2m/s to 10m/s in a distance of 10m. What is his acceleration?
DedPeter [7]

d = v·t + (1/2)·a·t^2

a = 10m/s^2. t = 10s

v = 0m/s. Initial velocity

d = 0·10 + 10/2 · 10^2 = 0 +5·100

d = 500m

8 0
2 years ago
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