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MariettaO [177]
3 years ago
6

Which statements describe projectile motion? Check all that apply.

Physics
2 answers:
miv72 [106K]3 years ago
5 0

In projectile motion we can say initial components of velocity is

v_x = v_0 cos\theta

v_y = v_0 sin\theta

now here horizontal motion is uniform motion as there is no force in this direction while in vertical direction due to gravity it will accelerate

so we have

x = v_0 cos\theta * t

y = v_0 sin\theta * t - \frac{1}{2}gt^2

so here we have x and y coordinates are related to each other as it will take same time to move the positions

so here correct options are

<em>Projectile motion is a combination of horizontal and vertical motion. </em>

<em>The horizontal and vertical motions of a projectile are dependent on each other.</em>

nlexa [21]3 years ago
5 0

Answer:

C. Projectile motion is a combination of horizontal and vertical motion.

D. The horizontal and vertical motions of a projectile are independent.

Explanation:

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Work = force * distance
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SCALCET8 3.9.018.MI. A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the
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Answer:

The length of his shadow is decreasing at a rate of 1.13 m/s

Explanation:

The ray of light hitting the ground forms a right angled triangle of height H, which is the height of the building and width, D which is the distance of the tip of the shadow from the building.

Also, the height of the man, h which is parallel to H forms a right-angled triangle of width, L which is the length of the shadow.

By similar triangles,

H/D = h/L

L = hD/H

Also, when the man is 4 m from the building, the length of his shadow is L = D - 4

So, D - 4 = hD/H

H(D - 4) = hD

H = hD/(D - 4)

Since h = 2 m and D = 12 m,

H = 2 m × 12 m/(12 m - 4 m)

H = 24 m²/8 m

H = 3 m

Since L = hD/H

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dL/dt = d(hD/H)/dt

dL/dt = h(dD/dt)/H

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Since h = 2 m and H = 3 m,

dL/dt = h(dD/dt)/H

dL/dt = 2 m(-1.7 m/s)/3 m

dL/dt = -3.4/3 m/s

dL/dt = -1.13 m/s

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3 years ago
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E=P\times t\\\\E=800\ W\times 1800\ s\\\\E=1440000\ J\\\\\text{or}\\\\E=1440\ kJ

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