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salantis [7]
3 years ago
11

A 750 kg car is moving at 20.0 m/s at a height of 5.0 m above the bottom of a hill when it runs out of gas. From there, the car

coasts. a. Ignoring frictional forces and air resistance, what is the car’s kinetic energy and velocity at the bottom of the hill
Physics
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

Explanation:

Kinetic energy at the height = 1/2 m v²

= 1/2 x 750 x 20²

= 150000 J

Its potential energy = mgh

= 750 x 9.8 x 5

=36750 J

Total energy = 186750 J

Its total kinetic energy will be equal to 186750 J , according to conservation of mechanical energy

If v be its velocity at the bottom

1/2 m v² = 186750

v = √498

= 22.31 m /s

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An ultrasonic ruler, such as the one discussed in Example 4 in Section 16.6, displays the distance between the ruler and an obje
garik1379 [7]

Answer:

reading would be 5.413 m.

Explanation:

Given:-

- The actual distance from ruler to an object is d = 24.0 m

- The adiabatic bulk modulus, B = 2.37 *10^9 Pa

- The density of seawater, ρ = 1025 kg/m^3

- The preset value of speed of sound in air, v_th = 343 m/s.

Find:-

Determine the distance reading that the ruler displays.

Solution:-

- We will first determine the actual speed of the sound ( v_a) in sea-water which can be determined from the following formula:

                            v_a = √ (B /  ρ )

- Plug in the values in the relationship above and compute v_a:

                            v_a = √ ( 2.37 *10^9 /  1025  )        

                            v_a = 1520.59038 m/s

- The time taken (t) for for the sound to travel from source(ruler) to an object which is d distance away.

                            d = v_a*t

                            t = d / v_a

                            t = 24.0 / 1520.59038

                            t = 0.01578 s

- The distance reading on the ruler would be preset speed (v_th) of sound in air multiplied by the time taken(t).

                           reading = v_th*t

                           reading = (343)*(0.01578)

                                         = 5.413 m

6 0
4 years ago
A thug pushes some 100 kg punk with 300 N of force. How much is the punk accelerated?
astra-53 [7]

Answer:

Acceleration generate by punk = 3 m/s²

Explanation:

Given:

Weight of punk = 100 Kg

Force applied on punk = 300 N

Find:

Acceleration generate by punk = ?

Computation:

Acceleration = Force / Mass

Acceleration generate by punk = Force applied on punk / Weight of punk

Acceleration generate by punk = 300 N / 100 Kg

Acceleration generate by punk = 3 m/s²

5 0
3 years ago
A man kicks the 150-g ball such that it leaves the ground at an angle of 60° and strikes the ground at the same elevation a dist
egoroff_w [7]

Answer:

313.92\ \text{m/s}

47.088\ \text{kg m/s}

Explanation:

m = Mass of ball = 150 g

\theta = Angle of kick = 60^{\circ}

x = Displacement of ball in x direction = 12 m

Range of projectile is given by

x=\dfrac{u\sin^2\theta}{2g}\\\Rightarrow u=\dfrac{2xg}{\sin^2\theta}\\\Rightarrow u=\dfrac{2\times 12\times 9.81}{\sin^260^{\circ}}\\\Rightarrow u=313.92\ \text{m/s}

The velocity of the ball instantly after the man kicks the ball is 313.92\ \text{m/s}

Impulse is given by

J=mu\\\Rightarrow J=0.15\times 313.92\\\Rightarrow J=47.088\ \text{kg m/s}

The impulse of his foot on the ball is 47.088\ \text{kg m/s}.

3 0
3 years ago
You can increase your flexiablity by streaching your bones / muscles
Vlada [557]
You can increase your flexibility by stretching with your muscles because when you stretch your muscles get stronger.
 hopes this helps you.<span />
7 0
3 years ago
If the speed and mass of an object are doubled, which of the following is true?
Harman [31]

Answer:

A is true

Explanation:

Other all are wrong I guess

7 0
3 years ago
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