3 years ago

Peer pressure is the influence that _________ may have on you

Physics

2 answers:

KonstantinChe [14]3 years ago

8 0

Both c and a could be right but I am steering more towards a.

Nastasia [14]3 years ago

3 0

A.) people your age

hope it helped

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Rock at the top of a 20 m tall hill the rock has a mass of 10 kg how much potential energy does it have

Blizzard [7]

PE = 10 * 10 * 20 = 2000 Joule

6 0

3 years ago

Read 2 more answers

A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.

worty [1.4K]

F= ma; a= F/m

a = 26.4 N/60 kg= 0.44 m/s^2

4 0

3 years ago

Two boxes are at rest on a smooth, horizontal surface. The boxes are in contact with one another. If box 1 is pushed with a forc

Maslowich

Answer:

mass of box 1 = 2.20 kg

mass of box 2 = 5.93 kg

Explanation:

Let the mass of box 1 and box 2 is respectively

$m_1$ and $m_2$

so we will have

Force applied on box 1 then acceleration

$a = \frac{F}{m_1 + m_2}$

$1.50 = \frac{12.2}{m_1 + m_2}$

$m_1 + m_2 = 8.13$

Now we know that contact force between them in above case is given as

$F_n = m_2a$

$8.90 = m_2(1.5)$

$m_2 = 5.93 kg$

now we have

$m_1 = 2.20 kg$

8 0

2 years ago

Does a car that is slowing down always have a negative acceleration explain

Zina [86]

No, because sometimes you have to stop at stop signs and stop lights.

4 0

3 years ago

The existence of the dwarf planet Pluto was proposed based on irregularities in Neptune's orbit. Pluto was subsequently discover

givi [52]

Answer:

Acceleration due to gravity, $a=4.61\times 10^{-14}\ m/s^2$

Explanation:

It is given that,

Mass of Pluto, $m=1.4\times 10^{22}\ kg$

Distance between Neptune and Pluto, $r=4.5\times 10^{12}\ m$

The force of gravity is balanced by the gravitational force between Neptune and Pluto. It is given by :

$a=\dfrac{Gm}{r^2}$

$a=\dfrac{6.67\times 10^{-11}\times 1.4\times 10^{22}}{(4.5\times 10^{12})^2}$

$a=4.61\times 10^{-14}\ m/s^2$

So, the acceleration due to gravity at Neptune due to Pluto is $4.61\times 10^{-14}\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago