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Basile [38]
3 years ago
9

You Fire A Bullet Into A 3 Kg Wooden Block Attached To A Spring With Spring Constant 70 N/m. When The Bullet Strikes The Block,

The Spring Compresses. The Bullet Has A Mass Of 0.03 Kg And Strikes The Block With A Speed Of 200 M/s. What Is The Speed Of The Block And Bullet When They First Start Moving Together?
Physics
1 answer:
brilliants [131]3 years ago
7 0

here at the moment when bullet strikes the block it will have no external force on it

so here we can use momentum conservation

so we will have

P_i = P_f

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.03(200) + 3(0) = 0.03v + 3v

6 = 3.03v

v = \frac{6}{3.03}

v = 1.98 m/s

so they move together with speed 1.98 m/s

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Calcium chloride in an ionic compound. The calcium atom loses two electrons, and each chlorine atom gains one electron, to form a full outer shell of electrons.

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The capacitance of A conductor is affected by the presence of A second conductor that is uncharged and isolated electrically. Wh
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A truck travels at a constant speed of 45 kilometers per hour. How far does the truck travel in 20 minutes?
Mekhanik [1.2K]
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6 0
3 years ago
Find the change in velocity of a 369 g hockey puck subject to the force shown below.
Elena-2011 [213]

Answer:

The change in velocity is 15.83 [m/s]

Explanation:

Using the Newton's second law we have:

ΣF = m*a

The force in the graph is 185 N, therefore:

185=0.369*a\\Where\\a=acceleration made it by the force [m/s^2]

a=501.35[m/s^2]

Now using the following kinematic equation:

V^{2}=Vi^{2} + 2*a*(x-xi) \\where\\V=final velocity [m/s]\\Vi= initial velocity [m/s] = 0 the hockey disk is in rest when receives the hit.\\ x = Final position [m] = 0.4 m\\xi = initial position [m] = 0.15m\\

Now replacing the values:

V^{2}=0 + 2*501.35*(0.4-0.15)\\ \\V= 15.83[m/s]

3 0
3 years ago
A balloon drifts 140 m toward the west in 45 s; then the wind suddenly changes and the balloon flies 90 m toward the east in the
rusak2 [61]

Answer:

Explanation:

Given

1 ) 140 m west in 45 s .

2 ) 90 m east in 25 s .

a )

distance travelled in first 45 s = 140 m

b ) distance travelled in next 25 s = 90 m

c ) Total distance travelled = 140 m + 90 m

= 230 m

d ) average speed in first 45 s

= distance in 45 s  45

= 140 / 45 = 3.11 m /s

e ) average speed in next 25 s

distance in 25 s / 25

= 90 / 25 = 3.6 m /s

f ) average in entire trip

=  total distance / total time

= (140 + 90) / ( 25 + 45 )

= 3.28 m /s

g )

displacement in first 45 s = 140 m towards west

h )

displacement in next 25 s = 90 m towards east

i )

total displacement = 140 - 90

= 50 m towards west .

3 0
3 years ago
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