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Basile [38]
3 years ago
9

You Fire A Bullet Into A 3 Kg Wooden Block Attached To A Spring With Spring Constant 70 N/m. When The Bullet Strikes The Block,

The Spring Compresses. The Bullet Has A Mass Of 0.03 Kg And Strikes The Block With A Speed Of 200 M/s. What Is The Speed Of The Block And Bullet When They First Start Moving Together?
Physics
1 answer:
brilliants [131]3 years ago
7 0

here at the moment when bullet strikes the block it will have no external force on it

so here we can use momentum conservation

so we will have

P_i = P_f

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.03(200) + 3(0) = 0.03v + 3v

6 = 3.03v

v = \frac{6}{3.03}

v = 1.98 m/s

so they move together with speed 1.98 m/s

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Answer:

Bulb 1 has more resistance.

Explanation:

Given that,

Two lightbulbs work on a 120-V circuit.

The power of circuit 1, P₁ = 50 W

The power of circuit 2, P₂ = 100 W

We need to find the bulb that has a higher resistance.

The power of the bulb is given by :

P = \dfrac{V^2}{R}

For bulb 1,

R_1=\dfrac{V^2}{P_1}\\\\R_1=\dfrac{(120)^2}{50}\\\\R_1=288\ \Omega

For bulb 2,

R_2=\dfrac{V^2}{P_2}\\\\R_2=\dfrac{(120)^2}{100}\\\\R_2=144\ \Omega

So, bulb 1 has higher resistance.

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