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natulia [17]
3 years ago
9

How can we use variations in luminosity to set limits on the size of an active galactic nucleus?

Physics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

If we see an object brighten in 1 hour, we know that the object cannot be longer than 1 light-hour in size. If it were, light from the far side of the object would start arriving at our telescopes more than an hour after the light from the front side and we would see the brightening take longer time than an hour to occur.

Explanation:

To understand the question above, let us discuss what variations in luminosity is:

variations in luminosity are two distinct word coming together to form a phenomenon. They are concepts that help us to bring to our understanding how brightness of the Sun significantly affects or impacts on global warming.

Variations as a concept can be describes as the total energy the sun generates in term of output or emission which also can be refereed to as the Luminosity ratio. Luminosity can also be refereed to as a concept caused by changing dark (sunspot) that bright structures on the solar disk during the 11-year sunspot cycle.

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Mary wishes to lose 5 pounds before her vacation in approximately 5 weeks. Her average consumption is 2,100 kilocalories per day
nordsb [41]

Answer:

1,600 to 1,700 kilocalories per day

Explanation:

7 0
3 years ago
What is the change all living things undergo as the grow
Vladimir [108]
All of the change that living things undergo as they grow is called development. That is the name when the changes are within a single unit and over a period of time as short as a lifetime. When the change occurs over thousands of years then it's called evolution.
6 0
4 years ago
Starting from rest, a 2.3x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts
Harman [31]

Answer:

3.13 m/s

Explanation:

From the question,

Since the flea spring started from rest,

Ek = W................... Equation 1

Where Ek = Kinetic Energy of the flea spring, W = work done on the flea spring.

But,

Ek = 1/2mv²............ Equation 2

Where m = mass of the flea spring, v = flea's speed when it leaves the ground.

substitute equation 2 into equation 1

1/2mv² = W.................... Equation 3

make v the subject of the equation

v = √(2W/m)................. Equation 4

Given: W = 3.6×10⁻⁴ J, m = 2.3×10⁻⁴ kg

Substitute into equation 4

v = √[2×3.6×10⁻⁴ )/2.3×10⁻⁴]

v = 7.2/2.3

v = 3.13 m/s

Hence the flea's speed when it leaves the ground  = 3.13 m/s

4 0
3 years ago
An what would be needed to change an objects state of motion
VladimirAG [237]

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~done by cessly420

mark brainliest please

hope this helped   :)

8 0
4 years ago
A vector is 14.4 m long and
MaRussiya [10]

Answer:

Explanation:

The x-component is found in the magnitude of the vector times the cosine of the angle.

A_x=14.4cos133 and, to 3 sig dig,

A_x=-9.82m

3 0
3 years ago
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