Answer:
the radius of bigger loop = 6 cm
Explanation:
given,
two concentric current loops
smaller loop radius = 3.6 cm
]current in smaller loop = 12 A
current in the bigger loop = 20 A
magnetic field at the center of loop = 0
Radius of the bigger loop = ?
now, on solving
=
= 6 cm
hence, the radius of bigger loop = 6 cm
Answer:
f = 614.28 Hz
Explanation:
Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :
f = 614.28 Hz
So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.
Answer:
m = 2.31 Kg
Explanation:
given,
m₁ is the mass rest on the inclined plane = 1.5 Kg
inclination of plane = 30°
Kinetic friction = μ = 0.4
acceleration of the body = 2.68 m/s²
mass m is hanging = ?
using equation to solve
T - m₁g sin θ - μ m₁g cos θ = m₁ a
on the block on inclined plane there will be acting tension T on the string,
mg sin θ will be the force acting opposite to the tension on the string and a frictional force will be acting which will oppose moment which will be equal to μ m₁g cos θ
T = m₁(g sin θ + μ g cos θ + a )
T = 1.5 (9.8 x sin 30° + 0.4 x 9.8 x cos 30°+ 2.68 )
T = 16.46 N
now, forces on the other side of pulley
m g - T = m a
m (g - a ) = T
m = 2.31 Kg