Answer:
it leads to attraction, only because the total energy of the electron is negative. Therefore the electron moves closer to the proton rather than farther from it an attractive force.... Electrons are negatively charged and protons are positively charged.
Answer:
The Kinetic energy and mass are _directly_ proportional.
Explanation:
We know that Kinetic Energy is basically termed as the capacity of a body to do work.
Kinetic energy is often used to associate with moving objects, therefore, K.E is normally termed as the energy of motion.
The formula of K.E of an object of mass and velocity is defined
K.E = 1/2mv²
From the formula, it is clear that K.E is directly proportional to its mass and also directly proportional to the square of its velocity.
For example,
If A toy plane with a mass of 10 kg is flying at 20 m/s. Its K.E will be:
K.E = 1/2mv²
= 1/2(10)(20)²
= 1/2(10)(400)
= 5(400)
= 2000 J
Now, let suppose, if we double the mass of a toy plane i.e.
m = 20 kg
so
K.E = 1/2mv²
= 1/2(20)(20)²
= 1/2(20)(400)
= 10(400)
= 400 J
Therefore, the K.E is doubled when doubled the mass.
Therefore, the Kinetic energy and mass are _directly_ proportional.
It is a solid substance that has a conductivity between that of an insulator and that of most metals, either due to the addition of an impurity or because of temperature effects
Answer:
x = 0.54 m
y = 0.058 m
Explanation:
m = mass of the bullet = 16 g = 0.016 kg
v = speed of bullet before collision = 240 m/s
M = mass of the pendulum = 3.6 kg
L = length of the string = 2.5 m
h = height gained by the pendulum after collision
V = speed of the bullet and pendulum combination
Using conservation of momentum
m v = (m + M) V
(0.016) (240) = (0.016 + 3.6) V
V = 1.062 m/s
Using conservation of energy
Potential energy gained by bullet and pendulum combination = Kinetic energy of bullet and pendulum combination
(m + M) g h = (0.5) (m + M) V²
(9.8) h = (0.5) (1.062)²
h = 0.058 m
y = vertical displacement = h = 0.058 m
x = horizontal displacement
horizontal displacement is given as
x = sqrt(L² - (L - h)²)
x = sqrt(2.5² - (2.5 - 0.058)²)
x = 0.54 m
In component form, the displacement vectors become
• 350 m [S] ==> (0, -350) m
• 400 m [E 20° N] ==> (400 cos(20°), 400 sin(20°)) m
(which I interpret to mean 20° north of east]
• 550 m [N 10° W] ==> (550 cos(100°), 550 sin(100°)) m
Then the student's total displacement is the sum of these:
(0 + 400 cos(20°) + 550 cos(100°), -350 + 400 sin(20°) + 550 sin(100°)) m
≈ (280.371, 328.452) m
which leaves the student a distance of about 431.8 m from their starting point in a direction of around arctan(328.452/280.371) ≈ 50° from the horizontal, i.e. approximately 431.8 m [E 50° N].
