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zheka24 [161]
3 years ago
8

Halving the distance (i.e., decreasing by a factor of two) between two charged objects will cause the electrical force between t

hem to be ___ the initial force.

Physics
1 answer:
Tcecarenko [31]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

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The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the
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Answer:

The value is  P_{max} =  2.11 * 10^{6} \  W

Explanation:

From the question we are told that  

    The maximized electric field strength is  E =  3.0 \ MV/m = 3.0 *10^{6} \  V/m

     The diameter is  d =  1.5\ cm  =  0.015 \  m

Generally the cross -sectional area is mathematically represented as

 =>      A =  \frac{\pi * d^2 }{4}

 =>      A =  \frac{3.142  * 0.015^2 }{4}

 =>      A = 0.0001767 \  m^2

Generally the maximum power is mathematically represented as

       P_{max} =  \frac{E_{max}^2}{ 2 * \mu_o * c }  *  A

Here c is the speed of light with value  c =  3.0 *10^{8} \  m/s

        \mu_o is the permeability of free space with value  \mu_o  = 4 \pi *10^{-7} \  H/m

      P_{max} =  \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} }  *   0.0001767

=>   P_{max} =  2.11 * 10^{6} \  W

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