Answer:
E_aprox = 1.003 E_real
Explanation:
In this exercise we are given the expression for the electric field of a dipole in the axis direction of the dipole
E_real = k 2q d / √(z² + d²)³
I think your equation has some errors.
In this case they indicate that d is the separation of the charges of the dipole
in the case of z »d this equations approximates
E_aprox = k 2q d/ z³
calculate the value for the two cases
E_real = k2q d / √[ ((23d)² + d²)³]
E_real = k2q d / d³ 12201
E_real = k2q 1/12201 d²
E_aprox = k2q d / (23.00d)³
E_aprox = k2q 1/12167 d²
the error between these quantities is
E_aprox / E_real = 12201 d² / 12167 d²
E_aprox / E_real = 1.003
E_aprox = 1.003 E_real
Answer:
d = 23.75 m
The zebra has gone 23.75m after 5 seconds.
Corrected question;
A zebra starts from rest and accelerates at 1.9 m/s2. How far has the zebra gone after 5 seconds.
Explanation:
From the equation of motion;
d = vt + 0.5at^2 .........1
Where;
d = displacement
v = initial velocity = 0
t = time taken= 5 seconds
a = acceleration = 1.9 m/s^2
Substituting the given values into equation 1;
d = 0(5) + 0.5(1.9×5^2)
d = 0.5(1.9×5^2)
d = 23.75 m
The zebra has gone 23.75m after 5 seconds.
I’m pretty sure the answer would be :
9.8m/s2
Explanation: gravity =9.8m/s2
<span>Magma is composed of molten rock and is stored in the Earth's crust. Lava is magma that reaches the surface of our planet through a volcano vent. Lavaflow, Hawai</span>
A) Oil B) Wood C) 0.02J D) 3g E) Gas
