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zheka24 [161]
3 years ago
8

Halving the distance (i.e., decreasing by a factor of two) between two charged objects will cause the electrical force between t

hem to be ___ the initial force.

Physics
1 answer:
Tcecarenko [31]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

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A ranger in a national park is driving at 56 km/h when a deer jumps onto the road 65 m ahead of the vehicle. After a reaction ti
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Answer:

 t = 1.58 s

Explanation:

given,

Speed of ranger, v = 56 km/h

                            v = 56 x 0.278 = 15.57 m/s

distance, d = 65 m

deceleration,a = 3 m/s²

reaction time = ?

using stopping distance formula

d = v. t + \dfrac{v^2}{2a}

t = \dfrac{d}{v} -\dfrac{v}{2a}

t is the reaction time

t = \dfrac{65}{15.57} -\dfrac{15.57}{2\times 3}

 t = 1.58 s

hence, the reaction time of the ranger is equal to 1.58 s.

3 0
3 years ago
The wavelength of light mainly affects our perception of
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Answer:

I would think the answer is color, if the wavelength is within the visible light spectrum. This could be answered in different ways but I'm pretty sure the answer you are looking for is hue/color.

6 0
3 years ago
How would your mass change if you took a trip to the space station? 1. no change in mass 2. decreases; you weigh less. 3. increa
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No chande in mass becouse of the change in gravitational force do not effect in mass
5 0
3 years ago
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A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally
stepladder [879]

Answer:  well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.  

The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]  

so t = sqrt(2*100/9.8) = 4.52s.  

The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s  

The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.  

so the final velocity is = sqrt(44.3^2 + 14.4^2) = 46.6m/s

Explanation: yes

6 0
3 years ago
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A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located
nadezda [96]

Answer:

\Delta V = 30V

Explanation:

give data:

inside diameter = 5.0 cm

charge q = 0.25 nC

Outside diameter = 15 cm

potential V at inside sphere is = V=\frac{kq}{R}

potential V at outside sphere is = V=\frac{kq}{r}

k is constant whose value is = 8.99 *10^{9}Nm^{2}/c^2

then potential difference between two point is

\Delta V = kq \left [\frac{1}{R}-\frac{1}{r}  \right ]

\Delta V = 9*10^{9}*0.25*10^{-9} \left [\frac{1}{0.05}-\frac{1}{0.15} \right ]

\Delta V = 30V

6 0
4 years ago
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