What is the mass of 3.62X10^24 molecules of methanol
2 answers:
Answer:
192.42 g [tex] CH_ {3} OH [/ tex]
Explanation:
The chemical formula of methanol is [tex] CH 3 OH [/ tex]
we calculate the molecular mass of the compound
C 12 g / mol
H 4 (1 g / mol)
Or 16 g / mol
[tex] (12 + 4 + 16) g / mol = 32 g / mol [/ tex]
We know that 1 mole of [tex] CH 3 OH [/ tex] has [tex] (6.02) 10 {23} [/ tex] molecules of [tex] CH 3 {OH] / and these have a mass of 32 g.
Now we calculate the mass of [tex] 3.62 /cdot10 {24} [/ tex] molecules of [tex] CH 3 OH [/ tex]
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ii. Given the dissolution of some substance
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the Ksp, or the solubility product constant, of the preceding equation takes the general form
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The concentrations of pure solids (like substance A) and liquids are excluded from the equilibrium expression.
So, given our dissociation equation in question i., our Ksp expression would be written as:
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