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Minchanka [31]
3 years ago
15

How does temperature affect the state of matter

Chemistry
1 answer:
Tom [10]3 years ago
8 0
Temperature is very important if ice gets too hot it turns to water, if it gets even hotter it turns to gas.

but if it’s too cold water can turn into ice

Temperature determines what state of matter something is
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The products of a chemical reaction are chemically different substances than the reactants of a chemical reaction.
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this statement is true

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Which best describes mitochondrial DNA (mtDNA)?
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People have different dna

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Gasoline contains only hydrogen and carbon atoms, yet nitrogen oxide and nitrogen dioxide are produced when gasoline burns. What
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Answer:

The answer to the question is

The source of the nitro- gen and oxygen atoms is from the atmosphere

Explanation:

When gasoline burns oxygen from the atmosphere supports the combustion reaction.

For example the internal combustion engine of a motor vehicle pulls in air from the surrounding atmosphere to make use of the oxygen in aiding the combustion of the gasoline to drive the pistons that ultimately moves the vehicle. The air from which the oxygen is absorbed also contains more amount of Nitrogen by percentage than oxygen. The nitrogen therefore enters into the combustion reaction that eventually produces nitrogen oxide and nitrogen dioxide

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In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌
Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of  CO = 0.35 mole

Volume of container = 1 L

Initial concentration of CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M

Initial moles of  H_2O = 0.40 mole

Volume of container = 1 L

Initial concentration of H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M

equilibrium concentration of CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M [/tex]

The given balanced equilibrium reaction is,

                            CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}

K_c=\frac{x\times x}{(0.40-x)(0.35-x)}

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}

K_c=0.70

Thus the value of the equilibrium constant is 0.70.

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Which statement is true about covalent AND ionic bonds?
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Answer:

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