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lyudmila [28]
2 years ago
10

What is a rule for determining the mass number of an atom or ion?

Chemistry
1 answer:
Semenov [28]2 years ago
7 0

Answer:

The mass number of the atom is equal to the sum of the number of protons and neutrons in the nucleus

Explanation:

Each proton and each neutron weigh one amu( atomic mass unit), adding together the neutrons and protons and multiplying by 1 amu you get the mass of an atom

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How many molecules are in 100 g of C6H120,?*​
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Answer:

3.37 × 10²³ molecules

Explanation:

Given data:

Mass of C₆H₁₂O₆ = 100 g

Number of molecules = ?

Solution:

Number of moles of C₆H₁₂O₆:

Number of moles = mass/molar mass

Number of moles = 100 g/ 180.16 g/mol

Number of moles = 0.56 mol

Number of molecules:

1 mole contain 6.022 × 10²³ molecules

0.56 mol × 6.022 × 10²³ molecules /1 mol

3.37 × 10²³ molecules

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What happens when a nitrogen molecule is formed from two nitrogen atoms?
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They form a covalent bond

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107.854 how many significant
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Answer:

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Explanation:

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6 0
3 years ago
What is the composition, in atom percent, of an alloy that contains a) 44.5 lbm of silver, b) 84.7 lbm of gold, and c) 7.3 lbm o
Fed [463]

<u>Answer:</u> The atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

<u>Explanation:</u>

To convert the given masses into grams, we use the conversion factor:

1 lb = 453.6 grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ......(1)

To calculate the atom percent of substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Moles of substance}\times N_A}{\text{Total moles of sample}\times N_A}\times 100     ......(2)

where,

N_A = Avogadro's number

  • <u>Moles of Silver:</u>

Mass of silver = 44.5 lb = 20185.2 grams

We know that:

Molar mass of silver = 107.87 g/mol

Putting values in equation 1, we get:

\text{Moles of silver}=\frac{20185.2g}{107.87g/mol}=187.12mol

  • <u>Moles of Gold:</u>

Mass of gold = 84.7 lb = 38419.9 grams

We know that:

Molar mass of gold = 196.97 g/mol

Putting values in equation 1, we get:

\text{Moles of gold}=\frac{38419.9g}{196.97g/mol}=195.05mol

  • <u>Moles of Copper:</u>

Mass of copper = 7.3 lb = 3311.3 grams

We know that:

Molar mass of copper = 63.55 g/mol

Putting values in equation 1, we get:

\text{Moles of copper}=\frac{3311.3g}{63.55g/mol}=52.10mol

Total moles of the sample =

  • <u>For Silver:</u>

Moles of silver = 187.12 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of silver}=\frac{187.12\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of silver}=43.08\%

  • <u>For Gold:</u>

Moles of gold = 195.05 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of gold}=\frac{195.05\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of gold}=44.93\%

  • <u>For Copper:</u>

Moles of copper = 52.10 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of copper}=\frac{52.10\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of copper}=11.99\%

Hence, the atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

3 0
3 years ago
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