Question

Slope and point of 3y=x+11

Answer 1

Slope formula is y = mx + b

Isolate the y. Divide 3 from both sides

3y = x + 11

(3y)/3 = (x + 11)/3

y = (x + 11)/3

Set y = 0.

0 = (1x + 11)/3

Slope = 1/3

Solve for x.

0(3) = (x + 11)/3(3)

0 = x + 11

0 (-11) = x + 11 (-11)

x = 0 - 11

x = 11

hope this helps

Answer 2

Point slope form is $(y-y_1)=m(x-x_1)$ where $(x_1,y_1)$ are a point that the line passes through and $m$ is the slope
I guess solve for 1 y and get the constants to the left side3y=x+11divide both sides by 3$y=\frac{1}{3}(x+11)$there you have it:$y-0=\frac{1}{3}(x-(-11))$it passes through the point (-11,0) and has a slope of 1/3