What is 400 percent as a mixed number?

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

You can put 400/100 to get the fraction 4/1 or 4, it is not a mixed number though. So the final answer is 4

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I need the 68th term help plz

Svet_ta [14]

Answer:

Since -14 is added in each term

Therefore,in 68 th term will be 68×-14 +(-19)

As the 1 st term is -19

68 th term= -952+(-19)

68 th term= -971

8 0

3 years ago

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb

Irina18 [472]

Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

2.50x+3.50(4)<30

2.50x+14 <30

2.50x<30- 14 Subtracting 14 from each sides.

2.50x< 16

$\frac{2.50x}{2.50}$ Dividing each sides by 2.50.

x<6.4

Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

Hope this helps!!

8 0

3 years ago

Find the angle between the vectors u=i-9j and v=8i+5j

Katyanochek1 [597]

Answer: $\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}$

Step-by-step explanation:

$u \cdot v=(1)(8)+(-9)(5)=-37\\\\|u|=\sqrt{1^{2}+(-9)^{2}}=\sqrt{82}\\\\|v|=\sqrt{8^{2}+5^{2}}=\sqrt{89}\\\\\cos \theta=\frac{-37}{\sqrt{82}\sqrt{89}}\\\\\theta=\cos^{-1} \left(\frac{-37}{\sqrt{82}\sqrt{89}} \right)\\\\\theta=\boxed{\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}}$