A broader definition of corrosion is the destructive attack on a metal through interaction with its environment. It is the process by which metallic atoms leave the compounds in the presence of water or gas. Metal atoms leave the metal until it fails or erodes from oxidation.
The tendency for oxidation is dependent on the metal. Metals used in construction, such as steel and copper alloys, are both subject to corrosion. Metals are chemical combinations of multiple elements. These metals are highly vulnerable because of the high energy content of the elements used in metallic form. The energy content is higher than that of their ores, allowing corrosion to become a natural process. Through being present in their natural environments, the ores in the metal revert back to their original form. For example, iron in moist air becomes iron oxide.
The resulting rust is a generic term for when iron corrodes. The reaction between iron and water causes rust to form on a metal object.
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Answer:
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Explanation:
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
<h3>What is molarity?</h3>
Molarity (M) is a unit of concentration of solutions, and it is defined as the moles of a solute per liters of a solution.
- Step 1: Calculate the liters of solution required.
A chemist has a 3.00 M KBr solution and wants to measure 0.733 moles of KBr. The required volume is:
0.733 mol × (1 L/3.00 mol) = 0.244 L
- Step 2: Convert 0.244 L to mL.
We will use the conversion factor 1 L = 1000 mL.
0.244 L × (1000 mL/1 L) = 244 mL
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
Learn more about molarity here: brainly.com/question/9118107
Answer:
nature of the core material, strength of the current passing through the core
Explanation:
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Answer:
The concentration of Cl in the solution is 1 M (option E)
Explanation:
MgCl₂ is an ionic compound, where subscript 2 indicates that it contributes 2 anions (negatively charged ions) Cl- to the solution. And you know that 0.20 moles of MgCl₂ are dissolved in water. Then, by multiplying this amount by the subscript, you get the amount of the chlorine ion Cl- that contributes the MgCl₂ compound to the solution. Then it is obtained that said compound contributes 0.40 moles of the Cl- anion.
With a thought similar to the previous case, it can be seen that in this case 0.10 mol of the ionic compound KCl is dissolved in water, and that this compound in turn contributes only a Cl- anion to the solution. Then the KCl compound provides 0.10 moles of the Cl- anion.
On the other hand, molarity is the number of moles of solute that are dissolved in a given volume. It is expressed in the units (moles/liter).
Then, the volume in which the compounds are dissolved in the corresponding unit of measure must be expressed, that is to say in L. Knowing that 1 L is 1000 mL, then 500 mL represents 0.50 L.
And knowing that the MgCl₂ compound contributes 0.40 moles of the Cl- anion while the KCl compound contributes 0.10 moles of the anion, it is possible to say that in total there are 0.50 moles of the Clons present anion in the solution.
So:
<u><em>concentration of Cl= 1 mol/L= 1 M</em></u>
<u><em>The concentration of Cl in the solution is 1 M (option E)</em></u>