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Mnenie [13.5K]
3 years ago
9

What is the answer A. North b. South C.east D west

Chemistry
1 answer:
ANTONII [103]3 years ago
5 0
I think it’s C because he would push off of the sled
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What volume of 9 M sodium hydroxide is required to make 500 mL of 0.1 M sodium hydroxide?
MArishka [77]

Answer:

6mL

Explanation:

V₁M₁ = V₂M₂

V₁ =  V₂M₂/M₁

V₁ = (500)(0.1)/(9)

V₁ = 5.56mL ≈ 6mL

3 0
3 years ago
What is the density of fresh water
Anna [14]

Answer:

about 1000 kg/m3

Explanation:

4 0
3 years ago
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Which is/are used in nuclear reactors to absorb neutrons?
daser333 [38]

Answer:

A. heavy nuclei

Explanation:

They absorb neuyrons in order to hain stability.

8 0
3 years ago
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How many moles of Calcium Oxide are needed to produce 4 moles of Calcium Hydroxide?
Tpy6a [65]

Taking into account the reaction stoichiometry, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CaO + H₂O → Ca(OH)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CaO: 1 mole
  • H₂O: 1 mole
  • Ca(OH)₂:  1 mole

<h3>Moles of CaO required</h3>

The following rule of three can be applied: If by stoichiometric reaction 1 mole of Ca(OH)₂ is produced by 1 mole of CaO, 2 moles of Ca(OH)₂ are produced by how many moles of CaO?

moles of CaO=\frac{2 moles of Ca(OH)_{2}x1 mol of CaO }{1 mole of Ca(OH)_{2}}

moles of CaO= 2 moles

Finally, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

5 0
2 years ago
Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to eff
dezoksy [38]

The molecular formula : As₄S₆

<h3>Further explanation</h3>

Given

Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms

Required

The molecular formula

Solution

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

Input the value :

1 = Arsenic(III) sulfide

2 = Ar

MM Ar = 40 g/mol

0.28 = √(40/M₁)

M₁=40 : 0.28²

M₁=510 g/mol

The empirical formula of arsenic(III) sulfide =  As₂S₃

(Empirical formula)n = molecular formula

( As₂S₃)n = 510 g/mol

(246.02 g/mol)n = 510 g/mol

n = 2

So the molecular formula : As₄S₆

5 0
3 years ago
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