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Afina-wow [57]
1 year ago
13

Please Help I need an explanation on how to do this

Chemistry
2 answers:
saw5 [17]1 year ago
6 0

Answer:

Balanced equation(That should be NaClO_3)

\begin{gathered}\\ \rm\Rrightarrow Cl_2+2NaOH\longrightarrow NaCl+NaClO_3+H_2O\end{gathered}⇛Cl2+2NaOH⟶NaCl+NaClO3+H2O

Remember that it's a ionic equation not general equation

So

We have to balance it accordingly

nydimaria [60]1 year ago
5 0

Balanced equation(That should be NaClO_3)

\\ \rm\Rrightarrow Cl_2+2NaOH\longrightarrow NaCl+NaClO_3+H_2O

Remember that it's a ionic equation not general equation

So

We have to balance it accordingly

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The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver
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Answer: Partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also,   P_{N_{2}} = x_{N_{2}}P

where,    P_{N_{2}} = partial pressure of N_{2}

                 P = atmospheric pressure

            x_{N_{2}} = mole fraction of N_{2}

Putting the given values into the above formula as follows.

      P_{N_{2}} = x_{N_{2}}P

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Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of N_{2} is as follows.

         P_{N_{2}} = x_{N_{2}}P

                  = 0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}

                  = 2964 mm Hg

Therefore, we can conclude that partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

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