The pressure of the atmosphere, when a barometer reads 780 mm Hg. Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2
This problem can be solved using the formula below
P = dgh................. Equation 1
Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.
From the question,
Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,
Constant: g = 10 m/s²
Substitute these values into equation 1
P = (1.36×10⁴)(10)(0.78)
P = 10.608×10⁴ N/m²
P ≈ 1.1×10⁵ N/m²
Hence the right answer is B. 1.1×10⁵ N/m²
Learn more about Pressure here: brainly.com/question/23603188
Answer:
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Answer:
Conservation of energy
Explanation:
The law of conservation of energy states that energy is usually conserved and is not produced, rather is is manipulated from one form to another.
Answer:
The speed of sound in the argon is 340 m/s.
Explanation:
Given;
fundamental frequency, f₀ = 200 Hz
length of the pipe, L = 42.5 cm = 0.425 m
A pipe that is open at one end and closed at another end is known as a closed pipe.
The wavelength for the first harmonic is calculated as;
L = Node -------> Antinode
L = λ/4
λ = 4L
The speed of the sound is calculated as;
v = fλ
where;
v is the speed of the sound
v = f x 4L
v = 200 x (4 x 0.425)
v = 340 m/s
Therefore, the speed of sound in the argon is 340 m/s.
Answer: 3.76 mm
Explanation: The formulae that defines the position of a nth fringe from the center of a double slit interference experiment is given below as
y =R×mλ/d
Where y = distance between the nth fringe and the center
R = distance between slits and screen = 1.71 m
m = position of fringe = 1
d = distance between slits = 0.254 mm = 0.000254m
λ = wavelength of light = 559 nm = 559×10^-9m
By substituting parameters, we have that
y = 1.71×1×559×10^-9/0.000254
y = 0.00000095589 / 0.000254
y = 0.00376m = 3.76 mm