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3 years ago

PLEASE HELP IF U PASS TESTS

Physics

2 answers:

Alexxandr [17]3 years ago

6 0

Iron. Is the correct answer

bezimeni [28]3 years ago

5 0

I think iron? i’m not 100% sure

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A person on another planet shines a flashlight at you. The planet and the earth are both in the same reference frame and are not

Nat2105 [25]

Assuming that they were at the exact distance away from you when they both turned on their lights your answer would be C. no matter how fast the person is moving light still travels at the same speed. please give brainliest

6 0

4 years ago

A 55-liter tank is full and contains 40kg of fuel. Find using Sl units: • Density p. • Specific Weight y • Specific Gravity Answ

Pavlova-9 [17]

Answer:

p = 727.273 kg/m3, y = 7134.545 N/m^3, SG = 0.7273

Explanation:

Density is simply the amount of mass of a substance per unit of volume. It can be found by dividing the mass in kg by the volume im m^3:

$p = \frac{m}{v} = \frac{40kg}{55lt*\frac{1 m^3}{1000 lt}} = 727.273 kg/m^3$

Specific weight is the weight of the substance per unit of volume. The weight is the mass of the material times the gravity, and it represents the force that the earth exerts on an object. Another way of calculate this value, its multiplying the density of the fuel times the gravity. Then:

$y = p*g = 727.273 kg/m^3 * 9.81 m/s^2 = 7134.545 N/m^3$

Specific Gravity is the ratio of the density of the substance to the density of a reference substance. For liquids, the reference substance is water at 4°C, which has a density of about 1000 kg/m^3.

$SG =\frac{ p_{fuel}}{p_{water}} = \frac{727.273 kg/m^3}{1000 kg/m^3} = 0.7273$

3 0

3 years ago

2. A jack exerts a vertical force of 4.5 X 103

skad [1K]

Correct Question:-

A jack exerts a vertical force of 4.5 × 10³

newtons to raise a car 0.25 meter. How much

work is done by the jack?

$\\ \\$

Given :-

$\star \sf \small force = 4.5 \times {10}^{3} \: newton$

$\star \sf \small distance = 0.25 \: meter$

$\\ \\$

To find:-

$\sf \star \: work = \: ?$

$\\ \\$

Solution:-

we know :-

$\bf \dag \boxed{ \rm work = force \times distance}$

$\\ \\$

So:-

$\dashrightarrow \sf work = force \times distance$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times 0.5 \\$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \frac{0 \cancel.5}{10} \\$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \frac{5}{10} \\$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \cancel \frac{5}{10} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{4\cancel.5}{10} \times 1 {0}^{3} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{10} \times 1 {0}^{3} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{10 {}^{0} } \times 1 {0}^{3 - 1} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{10 {}^{0} } \times 1 {0}^{2} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{1} \times 1 {0}^{2} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45 \times 10 \times \cancel{10}}{ \cancel2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45 \times 10 \times 5}{ 1} \\$

$\\ \\$

$\dashrightarrow \sf work =225 \times 10$

$\\ \\$

$\dashrightarrow \bf work =\red{2250\: joule}$

5 0

3 years ago

Which color in the visible spectrum has the highest frequency?<br> The Visible Light Spectrum

spayn [35]

Answer:

It Is violet

Explanation:

It has the shortest wavelengths and the shorter the wavelengths the higher the frequency.

8 0

3 years ago

Read 2 more answers

Fe has the electron configuration [Ar]3d64s2. What is the magnitude of the orbital angular momentum for its most energetic elect

salantis [7]

Answer : The magnitude of the orbital angular momentum for its most energetic electron is, $\sqrt{6}\hbar$

Explanation :

The formula used for orbital angular momentum is:

$L=\sqrt{l(l+1)}\hbar$

where,

L = orbital angular momentum

l = Azimuthal quantum number

As we are given the electronic configuration of Fe is, $[Ar]3d^64s^2$

Its most energetic electron will be for 3d electrons.

The value of azimuthal quantum number(l) of d orbital is, 2

That means, l = 2

Now put all the given values in the above formula, we get:

$L=\sqrt{2(2+1)}\hbar$

$L=\sqrt{6}\hbar$

Therefore, the magnitude of the orbital angular momentum for its most energetic electron is, $\sqrt{6}\hbar$

7 0

3 years ago