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fgiga [73]
3 years ago
8

a kid on a playground swing makes 6 complete to-and-from swings each 30 seconds (a) the frequency of the swinging is? (b) the pe

riod of the swinging is ?
Physics
2 answers:
Scorpion4ik [409]3 years ago
6 0

Show Me The Money 9 will likely be postponed until the fall instead of the summer, similar to the air dates of Show Me The Money 777, because of the Kung Flu pandemic going around.

Mariana [72]3 years ago
4 0

The frequency is how many per second:

       (6 swings)/(30 sec) = (6/30) swing/sec = 0.2 per sec = 0.2 Hz .

The period is how long each one takes, or seconds per swing.
It's exactly the flip of frequency.
So we could just take the frequency, flip it, and find   1 / 0.2 ,
but let's do it the long way:

      (30 sec) / (6 swings) = (30/6) sec/swing =  5 seconds  .  

      
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3 years ago
Which resistors in the circuit must have the same amount of charge passing through each second?
Nutka1998 [239]

Answer:

Option B) C and D

Explanation:

The amount of charge passing through a resistor each second corresponds to the definition of current, so the problem is asking "which resistors have the same amount of current".

Let's keep in mind that:

- When two resistors are in series (=they are connected into the same branch of the circuit), the current flowing through each resistor is the same

- When two resistors are in parallel (=they are connected into different branches), the potential difference across each resistor is the same

Looking at the previous definitions, we have to find the two resistors in the circuit that are connected in series. We see that resistors C and D are in the same branch, so they are in series: therefore, the current flowing through resistor C and D is the same.

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3 years ago
Which part of the eye is used to see things in high detail?
irina1246 [14]

Answer:

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7 0
2 years ago
An object is formed by attaching a uniform, thin rod with a mass of mr = 6.9 kg and length L = 4.88 m to a uniform sphere with m
Bumek [7]

Answer:

a)  total moment of inertia is 1359.05 kg m^2

b) angular acceleratio is 0.854rad/sec^2

Explanation:

Given data:

m1=6.9 kg

L=4.88 m

m2=34.5 kg

R=1.22 m

we klnow that moment of inertia for rod is given as

J1=(1/12) ×m×L^2

J1 = (1/12) \times 6.9 \times 4.88^2 = 13.693 kg m^2

moment of inertia for sphere is given as

J1=(2/5) ×m×r^2

J1 = (2/5) \times 34.5 \times 1.22^2 = 20.539 kg m^2

As object rotates around free end of rod then for sphere the axis around what it rotates is at a distance of d2=L+R

For rod distance is  d1=0.5*L

By Steiner theorem

for the rod we get J_1'=J_1 + m_1\times d_1^2

J_1' = 13.693 + 2.44^2\times 6.9 = 54.77 kg m^2

for the sphere we get J_2' = J_2 + m_2\times d_2^2

J2' = 20.539 + 34.5\times 6.1^2 = 1304.28 kg^m2

And the total moment of inertia for the first case is

J_{t1} = J_1'+J_2' = 54.77 + 1304.28 = 1359.05kg.m^2

b) F=476 N

The torque for system is given as

M = F\times d\times sin(a)

where a is angle between Force and distance d

and where d represent distance from rotating axis.

In this case a = 90 degree  

M = F\times L/2

M=476*2.44 = 1161.44 Nm

The acceleration is calculated as

a_1 = \frac{M}{J_{t1}}

      = \frac{1161.44}{1359.05}

      = 0.854 rad/sec^2

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3 years ago
Help me plsss! no links
Stolb23 [73]

Answer:

a is the answer to the question

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3 years ago
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