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kumpel [21]
3 years ago
14

If $1,800 is invested in a savings account offering interest at a rate of 4.5% per year, compounded continuously, how fast is th

e balance growing after 3 years
Physics
1 answer:
Archy [21]3 years ago
3 0

Answer:

The total amount  after 3 years is = $ 2054.10

Explanation:

Given data

Principal Amount (P) = $ 1800

Rate of interest (R) = 4.5 %

Thus the total amount after 3 years compounded annually is given by the formula =  P × [1 +\frac{R}{100}  ]^{3}

⇒ 1800 × [1 +\frac{4.5}{100}  ]^{3}

⇒ 2054.10

Thus the total amount  after 3 years is = $ 2054.10

Compound interest earned in three years = 2054.10 - 1800 = $ 254.10

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Answer:

Control rods

Explanation:

Control rods is unique to nuclear power plants as they are mainly used in nuclear reactors to stabilize the rate of fission of plutonium or uranium. They are usually composed of chemical elements such as cadmium, silver, boron, and indium.

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Heat is applied to an ice cube in a closed container until only steam is present. draw a representation of this process, assumin
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The density of water is 1g/cm3. What is this in kg/m3? The density of water is 1g/cm3. What is this in kg/m3? Follow 3 answers 3
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Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only
Ne4ueva [31]

Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

u is usually used for notation of initial notation.

Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

Acceleration: The difference of final velocity and initial velocity per unit time

The S.I unit of acceleration is m/s².

(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

v=u+at

Here v=0

⇒0=128+(-32) t

⇒32t=128

⇒t = 4 sec

To determine the height we use the following formula

s=ut+\frac{1}{2} at^2

\Rightarrow s= (128\times4)+\frac{1}{2}\times (-32) \times4^2

⇒s= 256 ft

Therefore the highest altitude attained by the object is =(320+256)ft=576 ft .

(b)

At the highest point the velocity of the object is 0.

so u=0. a=g= 32 ft/sec²  [ since the direction of gravity and the displacement are same] s= 576 ft

To determine the time to fall we use the following formula

s=ut+\frac{1}{2} at^2

\Rightarrow 576 = (0\times t)+\frac{1}{2} \times 32 \times t^2

\Rightarrow 16\times t^2=576

\Rightarrow t^2=\frac{576}{16}

\Rightarrow t^2=36

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

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