Answer:
So, given the eqn Fg=G(m1+m2/r^2) where G is the gravitational constant, m is the mass of the satellite and m2 is the mass of the earth and r is the distance from earth to the satellite, the force of earths gravity should be quartered.
Cause (2r)^2 gets turned into (4r^2) where 4r^2 is compared to r^2
Explanation:
Answer:
B = 0.0307 T = 30.74 mT
Explanation:
Given
m = 0.150 kg
I = 15.0 A
d = 0.510 m
μk = 0.16
B = ?
Balancing the forces on the rod in the <em>j</em> direction
N - m*g = 0 ⇒ N = m*g
and in the <em>i</em> direction
I*d*B - μk*N = 0 ⇒ B = μk*N / (I*d)
⇒ B = μk*m*g / (I*d)
⇒ B = (0.16)*(0.150 kg)*(9.8 m/s²) / (15.0 A*0.510 m)
⇒ B = 0.0307 T = 30.74 mT
