Answer: The mother of the man can be either XHXH or XHXh and pass her normal allele to the son and his father can be either XHY or XhY, he only passes his Y chromosome. The mother of the woman can be XHXH or XHXh and the father could be XhY, then she could have inherited the normal allele from the mother and the affected allele from the father. But also, the mother of the woman could be XHXh or XhXh and the father could be XHY, so in this case she could have inherited the normal alele from the father and the affected allele from the mother.
Explanation:
Hemophilia is an inherited bleeding disorder in which the blood does not clot properly. This can cause bleeding either spontaneously or after an injury.
<u>It is related to the X chromosome and it is recessive for females</u>, this mean they need both affected alleles to develop the trait. <u>Males only need one recessive allele because they only have one X chromosome</u>. This means that females need both parents to be at least carriers (although one or both can also have the disease or both recessive alleles). While males inherit it only from the mother, either she is a carrier (one recessive allele) or she has the disease (both recessive alleles). Then the mother passes the X chromosome with the affected allele to the son, and that son only receives the Y chromosome from the father, which does not have the gene that determines this disease.
If the mother is a carrier, her genotype is XHXh, being XH the normal allele and Xh the affected allele. She does not have hemophilia because she has a dominant allele. The father is XHY, so he does not have the disease because his only allele is normal (dominant)
The mother of the man can be either XHXH (she can only pass a normal allele) or XHXh and pass her normal allele to the son (in this case, the recessive allele is not inherited by chance.) His father can be either XHY or XhY, he only passes his Y chromosome which is not related to the disease. The mother of the woman can be XHXH or XHXh and the father could be XhY, then she could have inherited the normal allele from the mother and the affected allele from the father. But also, the mother of the woman could be XHXh or XhXh and the father could be XHY, so in this case she could have inherited the normal alele from the father and the affected allele from the mother.
Answer:
The correct answer is - c. CALM II psi3 (36 million years old)
Explanation:
Answer:
12:3:1
Explanation:
<em>The typical F2 ratio in cases of dominant epistasis is 12:3:1.</em>
<u>The epistasis is a form of gene interaction in which an allele in one locus interacts with and modifies the effects of alleles in another locus</u>. There are different types of epistasis depending on the type of alleles that are interacting. These include:
- Dominant/simple epistasis: Here, a dominant allele on one locus suppresses the expression of both alleles on another locus irrespective of whether they are dominant or recessive. Instead of the Mendelian dihybrid F2 ratio of 9:3:3:1, what is obtained is 12:3:1. Examples of this type of gene interaction are found in seed coat color in barley, skin color in mice, etc.
- Other types of epistasis include <em>recessive epistasis (9:3:4), dominant inhibitory epistasis (13:3), duplicate recessive epistasis (9:7), duplicate dominant epistasis (15:1), and polymeric gene interaction (9:6:1).</em>
Humans even though i dont believe in evolution but that is the scientific answer