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White raven [17]
3 years ago
6

How many moles of Ca[OH]2 are present in 80.0 g of Ca[OH]2?​

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

1.08mol

Explanation:

moles = reacting mass/ molecular weight

reacting mass = 80.0g molecular weight of Ca[OH]2= 40 + 2(16 +1) = 74g/mol

mole = 80.0/74 = 1.08mol

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