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nasty-shy [4]
2 years ago
6

What’s the answer to this? Pls help

Chemistry
1 answer:
Sedaia [141]2 years ago
7 0

Answer:

First choice

Explanation:

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Zn + 2HCI --> ZnCl2 + H2
Elena-2011 [213]
Moles= mass\ relative formula mass(Ar)
moles of zinc= 7.9/30= 0.263
so we have 0.263 moles of zinc, and you need twice the amount of chlorine so therefore 0.526moles of chlorine= 0.526x 17=8.942g of chlorine
i cba to work the rest out but the most reasonable answer is 0.24 mol however if you need to use working outs, use the formula i provided earlier
8 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
Heat the oxygen to about 150 K. What state of matter is this?
adelina 88 [10]

Answer:

  • <u>Gas</u>

Explanation:

It is easier if you convert the kelvin temperature into Celsius degrees:

  • ºC = T - 273.15 = 150 - 273.15 = -123.15ºC

Now, you know that that is a very cold temperature. Thus, may be the oxygen is not gas any more but it changed to liquid . . . or solid?

You must search for the boiling point and melting (freezing) point of oxygen in tables or the internet. At standard pressure (about 1 atm) they are:

  • Melting point: −218.79 °C,
  • Boiling point: −182.962 °C

That means that:

  • below -218.79ºC oxygen is solid (not our case).
  • between -218.79ºC and -182.962ºC oxygen is liquid (not our case)
  • over -182.962ºC oxygen is a gas. This is our case, because -123.15ºC is a higher temperature than -182.962ºC.

Hence, <em>the state of matter of oxygen at 150K</em>, and standard pressure, is gas.

3 0
3 years ago
Ethyl acetate is a sweet-smelling solvent used in varnishes and fingernail polish remover. it is produced industrially by heatin
Tatiana [17]
When Carboxylic Acid is treated with Alcohols in the presence of acid as a catalyst it produces corresponding Esters. This reaction is called as Esterification.
 Also, this reaction is a reversible reaction and the ester formed can also hydrolyze to produce Carboxylic acid and Alcohol. This reverse reaction is called as transesterification.
The formation of Ethyl Acetate from Acetic Acid and Ethanol in the presence of acid is shown below,

6 0
3 years ago
Write the balanced chemical reaction for the following nitrogen cycle reactions. These reactions are mediated by bacteria and pl
Leto [7]

Answer:

Nitrification is a biological process by which ammonia is oxidized to nitrites (NO_{2} ^{-}) and then to nitrates (NO_{3} ^{-}) by action of specialized bacteria in nature (such as <em>nitrosomonas</em> and <em>nitrobacter</em>).

Explanation:

This two-step process utilizes molecular atmospheric oxygen and ammonia and ammonium components of soil and nature.

<em>(a.) Ammonia and ammonium compounds to nitrite</em>

NH_{4} ^{+} + O_{2} → NO_{2} ^{-} + 4H^{+}

2NH_{3} ^{+} + 3O_{2} → 2NO_{2} ^{-} + 2H^{+} + 2H_{2} O

<em>(b.) Nitrite to nitrate</em>

2NO_{2} ^{-} + O_{2} → 2NO_{3} ^{-} + energy

<em>(c.) The reverse process involves reduction of nitrates to molecular nitrogen, called denitrification (with succinic acid in the equation below).</em>

4NO_{3} ^{-} + 10H^{+} + (CH_{2})_{2}(COOH)_{2} → 2N_{2} +4CO_{2}  + 8 H_{2} O

(NO and N_{2}O is an intermediate product in this process.)

4 0
3 years ago
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