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maksim [4K]
3 years ago
9

When oxygen is depleted, the citric acid cycle stops. What could we add to the system to restore citric acid cycle activity (oth

er than oxygen)?
Chemistry
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

NAD+, FAD.

Explanation:

The citric acid cycle is popularly known as the Kreb's cycle. The cycle involve the oxidation of acetyl-CoA to produce energy. The Kreb's cycle is a chemical process that produces produces two carbon dioxide molecules,NADH,FADH2 and one ATP.

When oxygen is depleted, the citric acid cycle stops, apart from oxygen NAD+ and FAD could be added to the system to restore citric acid cycle activity. NAD+ acts as an electron acceptor.

Citric acid cycle/Kreb's cycle is an aerobic process that occurs in the mitochondria and produces thirty-six(36) ATPs.

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Answer:

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Explanation:

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3 0
3 years ago
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What is the mass of solid NH4Cl formed when 75.5g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas remai
taurus [48]

Answer:The volume of the remaining gas that is ammonia is 23.85 L.

Explanation:

NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

Moles of NH_3=\frac{\text{mass of} NH_3}{\text{Molar mass of}NH_3}=\frac{75.5 g}{17.03 g/mol}=4.43 mole

Moles of HCl of gas = \frac{\text{mass of} HCl}{\text{Molar mass of}HCl}=\frac{75.5 g}{36.5 g/mol}=2.06 mol

According to reaction 1 mole of HCl reacts with 1 mol of NH_3 then 2.06 moles of HCl will react with = 2.06 moles of NH_3

Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles

Volume of the gas will be given by Ideal gas equation: PV=nRT

Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm

R = 0.08026 L atm/K mol

V = ? , n = number of moles of ammonia

Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)

V=\frac{2.36 mol\times 0.08206 L atm/K mol\times 287 K}{2.33 atm}=23.85 L

The volume of the remaining gas that is ammonia is 23.85 L.

8 0
3 years ago
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Please help ill give you a 100 points! Its urgent!! Q^Q
Sergio [31]

Answer:

1. C.

Explanation:

8 0
3 years ago
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What is the total energy needed to boil 255 grams of water, given that the
nexus9112 [7]

Answer:

  • <u>575,000 J</u>

Explanation:

<u>1) Convert the mass of water into number of moles</u>

  • Molar mass of water: 18.015 g/mol

  • Number of moles, n = mass in grams / molar mass

        n = 255 g / 18.015 g/mol = 14.15 mol

<u>2) Use the formula E = n × ΔH vap</u>

This is, you have to multiply the molar ΔH vaporization by the number of moles to find the total energy to boil the given amount of water.

  • E = 14.15 mol × 40,650 J/mol = 575,395.5 J

<u>3) Round to the correct number of significant figures.</u>

The mass of water is the measurement with the least number of significant figures (3), so you must report the answer with 3 significant figures,

  • E = 575,000 J ← answer
3 0
3 years ago
To make a 1.0L dilute of 0.5M from a stock solution of 12M, how much solution will be needed?
Cerrena [4.2K]

Answer:

V_{concentrated}=0.042L=4.2mL

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}

Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:

V_{concentrated}=\frac{M_{diluted}V_{diluted}}{M_{concentrated}} =\frac{0.5M*1.0L}{12M}\\ \\V_{concentrated}=0.042L=4.2mL

Best regards.

6 0
3 years ago
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