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attashe74 [19]
3 years ago
7

How many zeroes are significant in the measurement 0.0400200?

Chemistry
2 answers:
Ad libitum [116K]3 years ago
7 0

Answer:

4

Explanation:

if the 0 is in the beginning it is not significant.

0 in between are always significant.

the 0 at the end are only significant if theres a decimal.

Zarrin [17]3 years ago
4 0

Answer:

Explanation:

4

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Difference between shell and subshell?
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The "sub shells" are the orientations and shapes for your orbitals, going in order by Shells are a collection of subshells with the same principle quantum number, and subshells are a collection of orbitals with the same principle quantum number and angular momentum quantum number. Hope this helps :)
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2 years ago
Solid solutions that are mixtures of elements with metallic properties are known as_____
marshall27 [118]
Alloys. hope this helps.
4 0
2 years ago
An iron has a net charge of 3+. If this job has 8 protons, how many electrons does it have
kati45 [8]

Answer:

5 electrons

Explanation:

When an atom loses are gain the electrons ions are formed.

There are two types of ions.

Anion

Cation

1 = Anion

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X + e⁻ → X⁻

2= Cation

It is formed when an atom loses the electrons. when atom lose electron positive charge is created on atom. For example.

X → X⁺ + e⁻

When an atom loses three electrons +3 charge is created. If this atom have 8 protons it means there were 8 electrons too. When it lost three electrons then remaining number of electrons are 5.

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4 0
3 years ago
The rock was white and black speckled with a density of 2.6 g/mL. Physical or chemical property?
stepladder [879]

Answer:

Chemical

Explanation:

7 0
3 years ago
Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in
Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is  2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\   \frac{m_{S} }{m_{O} }= 2

Let us express it as

SO_{\frac{m_{S} }{m_{O} }} = 2

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\   \frac{m_{S} }{m_{O} }= 1

Let us express it as

SO_2_{\frac{m_{S} }{m_{O} }}= 1

Now, for the ratio of both the above-calculated ratios,

\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}

The required ratio is 2:1

3 0
2 years ago
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