What would most likely cause an increase in cloud formation?

the skydiver has a forward velocity of 40 m/s, After two second, what is the skydivers forward and downward velocity?

bogdanovich [222]

Initial velocity, u = 40 m/s
Final velocity, v = ?
t = 2s
g ≈ 9.8 m/s²

v = u + gt. Since it is a free fall, acceleration due to gravity, g

v = 40 + 9.8*2

v = 59.6 m/s

5 0

3 years ago

A spring is compressed 8 cm. It is then brought back to equilibrium and compressed 24 cm. How much more work is done in the seco

posledela

Answer:

Nine times

Explanation:

$x_{i}$ = Initial compression of the spring = 8 cm = 0.08 m

$x_{f}$ = Final compression of the spring = 24 cm = 0.24 m

$k$ = Spring constant of the spring

Initial spring energy is given as

$U_{i} = (0.5) k x_{i}^{2}\\U_{i} = (0.5) k (8)^{2}\\U_{i} = 32 k$

Initial spring energy is given as

$U_{f} = (0.5) k x_{f}^{2}\\U_{f} = (0.5) k (24)^{2}\\U_{f} = 288 k = (9) (32) k = 9 U_{i}$

3 0

4 years ago

What is the concentration of molecular oxygen (O2) in mol/L on a June day in Toronto when atmospheric pressure is 1.0 atm and th

saveliy_v [14]

Answer:

The concentration of mole evil at oxygen on that day is 0.00858 mol/L

Explanation:

Here, we want to calculate the concentration of molecular oxygen

The pressure on that day is 1.0 atm

Since oxygen is at a concentration of 21%, the pressure of oxygen will be 21/100 * 1 = 0.21 atm

Now let’s calculate the concentration;

From Ideal gas law;

PV = nRT

This can be written as;

P/RT = n/V

The term n/V refers to concentration;

Let’s make substitutions now;

P = pressure = 0.21 atm

R = molar gas constant = 0.0821 L•atm/mol•k

T = temperature = 25 = 25 + 273.15 = 298.15 K

Substituting these values, we have;

n/V = C = 0.21/(0.0821 * 298.15) = 0.00858 mol/L

6 0

3 years ago

Calculate the tension on the rope. A. 57.89 N B. 32.73 N C. 69.84 N D. 12.55 N

Ratling [72]

Hi there!

$\large\boxed{\text{B. 32.73N}}$

To calculate the tension, we must calculate the acceleration of the system.

Begin with a summation of forces:

∑F = -M₁gsinФ + T - T + M₂g

Simplify and solve for acceleration: (Tensions cancel out)

$a = \frac{-M_1gsin\theta + T - T + M_2g}{M_1+M_2}$

Plug in values. Let g = 10 m/s²

$a = \frac{-3(10)(sin30)+8(10)}{3+8} = 5.91 m/s^{2}$

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:

∑F = -T + W

ma = -T + W

Rearrange to solve for T:

T = W - ma

We know the acceleration, so plug in the values:

T = (8)(10) - (8)(5.91) = 32.73 N

3 0

3 years ago

A strong-armed physics student throws a tennis ball vertically. The ball stays in the air for 5.5 seconds. Assuming the ball lef

Mila [183]

Answer:

27.5 m/s

Explanation:

applying motion equations we can find the answer,

v = u + a*t

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

t = time taken for the motion

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero (only a vertical speed component is there)

for the complete motion it takes 5.5 s. that means to reach the highest point it will take 5.5/2 =2.75 seconds

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g=10 m/s2)

that is,

v = 0 , a = -10 $ms^{-2}$ , t =2.75

v = u + at

0 = u -10*2.75

u = 27.5 $ms^{-1}$

4 0

4 years ago