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omeli [17]
4 years ago
5

Gravitational force becomes (stronger/weaker)as mass increases

Physics
2 answers:
azamat4 years ago
8 0
Well Babygirl123 the gravitational force would increase or become stronger as the mass of a planet say Earth increases. while as a little planet such as Pluto has a little to no amount of gravitational force.
Mashcka [7]4 years ago
3 0
Stronger.....................becasue gravitational force is force pulling all matter (anything that has mass and occupies space) . The more the matter (which also includes mass), the more the gravitational force.
<span>So, the answer is stronger. </span>
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What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
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Answer:

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Explanation:

given,

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using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

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