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Inga [223]
3 years ago
10

How does an atom of potassium-41 become a potassium ion with a +1 charge? 19 K 39.10

Physics
2 answers:
patriot [66]3 years ago
6 0

Answer:

B. The atom loses 1 electron, to make a total of 18.

Explanation:

Since proton lies inside the nucleus of the atom so it is bounded strongly by the nuclear forces

So it is very difficult to charge an atom by transfer of protons as it need to work against nuclear forces

But electrons orbit around the nucleus in different energy state so all those electrons which are lying at the outermost orbit is loosely bound and hence it is easy to remove that electron.

Since potassium ion has atomic number 19

so for a neutral ion it has 19 electrons and 19 protons in it

now in order to make it a charge of +1

so we can remove one electron from it so that it has 19 protons and 18 electrons it so due to which it will have +1 charge on it

so correct answer will be

B. The atom loses 1 electron, to make a total of 18.

stiv31 [10]3 years ago
5 0

It is very difficult for an atom to accept a proton. It can only be done under very special circumstances. So A and C are both incorrect. I don't see how D is possible. The atom does lose 1 electron, but how it gets 21 is think air.

The answer is B which is exactly what happens.

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A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50
asambeis [7]

Answer:

The capacitance per unit length is 5.06\times10^{-11}\ F/m

(b) is correct option.

Explanation:

Given that,

Radius a= 2.50 mm

Radius b=7.50 mm

Dielectric constant = 3.68

Potential difference = 120 V

We need to calculate charge per length for the capacitance

Using formula of charge per length

\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}

Put the value into the formula

\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}

\lambda=6.068\times10^{-9}\ C/m

We know that,

\lambda=\dfrac{Q}{L}

We need to calculate the capacitance per unit length

Using formula of capacitance per unit length

C=\dfrac{\dfrac{Q}{L}}{\Delta V}

C=\dfrac{6.068\times10^{-9}}{120}

C=5.06\times10^{-11}\ F/m

Hence, The capacitance per unit length is 5.06\times10^{-11}\ F/m

7 0
3 years ago
Will a series circuit work if there are two batteries and one light bulb? Help asappp please!
Dmitry_Shevchenko [17]

Answer:

Doubling the voltage in this arrangement both doubles the voltage drop across the resistor and the current through it. The bulb will be much brighter.

7 0
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vivado [14]

Answer:

A box sits stationary  on a ramp

Explanation:

Static friction is a force which keeps an object at rest as it is in the case of the box. It has to be overcome for the object to be set into motion.

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spayn [35]
The hardest part of the job is to find the right formula to use, and write it down. You've already done that ! The rest is just turning the crank until an answer falls out.

You wrote. E = m g h.
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You know all the numbers on the right side. Just pluggum in, do the arithmetic, and you'll have the mass.
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