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Inga [223]
3 years ago
10

How does an atom of potassium-41 become a potassium ion with a +1 charge? 19 K 39.10

Physics
2 answers:
patriot [66]3 years ago
6 0

Answer:

B. The atom loses 1 electron, to make a total of 18.

Explanation:

Since proton lies inside the nucleus of the atom so it is bounded strongly by the nuclear forces

So it is very difficult to charge an atom by transfer of protons as it need to work against nuclear forces

But electrons orbit around the nucleus in different energy state so all those electrons which are lying at the outermost orbit is loosely bound and hence it is easy to remove that electron.

Since potassium ion has atomic number 19

so for a neutral ion it has 19 electrons and 19 protons in it

now in order to make it a charge of +1

so we can remove one electron from it so that it has 19 protons and 18 electrons it so due to which it will have +1 charge on it

so correct answer will be

B. The atom loses 1 electron, to make a total of 18.

stiv31 [10]3 years ago
5 0

It is very difficult for an atom to accept a proton. It can only be done under very special circumstances. So A and C are both incorrect. I don't see how D is possible. The atom does lose 1 electron, but how it gets 21 is think air.

The answer is B which is exactly what happens.

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Which two statements describe reasons that semiconductors must be
Cerrena [4.2K]

Answer:

They provide a source of electrons to be released by the photoelectric effect, and They provide a path through which released electrons move to form an electric current.

Explanation:

A p e x

6 0
3 years ago
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Interpret the following graph
tankabanditka [31]

Answer:

from O toWl Q partical is accelerating with constant magnitude. and from Q to P is decelerating with constant magnitude.

Explanation:

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3 0
2 years ago
The peak wavelength of light coming from a giant red star is 660 nm. Calculate the approximate surface temperature of this star
laiz [17]

Answer:

The value is T =260.33 \ F

Explanation:

From the question we are told that  

  The the peak wavelength is  \lambda_p =  660 nm = 660 *10^{-9} \  m

 Generally according to the Wien's displacement law

       \lambda_p *  T =  2.898*10^{-3} \ m \cdot K  

Here T is the approximate surface temperature of this star in K so

       660*10^{-9} *  T =  2.898*10^{-3} \ m \cdot K  

=>    T =  4091 \  K

Converting to Fahrenheit ,

     T = [400 - 273.15 ] * \frac{9}{5} + 32

=>  T =260.33 \ F

5 0
2 years ago
In the lab you place a beaker that is half full of water (density pw ) on a scale. You now use a light string to suspend a piece
Radda [10]

Answer:

N2- N1 = \rho_{w}  V g

Explanation:

Let's use for this exercised the equilibrium relationship

        ∑ F = 0

        N -W = 0

        N = W = mg

Let's use density redefinition

       ρ = m / v

       m = ρ V

       N₁ = (ρ V) g

Repeat for when the liquid is submerged, in this case an upward thrust appears as a result of the water dispensed (rgow)

        N₂ + B - W = 0

        N₂ = W - B

        B = m_{water} g

        \rho_{w} = m / V

         m_{w}  =  \rho_{w}  V

        N = ρ V g -  \rho_{w}  Vg

        N2 = N1 +   \rho_{w}  V g

        N2- N1 = \rho_{w}  V g

6 0
3 years ago
A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.
ValentinkaMS [17]

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

v = 1.74 x 10^{3}  ( \frac{m}{s} )

\alpha = 58°

v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )

v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)

v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\

t= \frac{2*v_{y} }{g}

t= \frac{2*1475.603 }{9.8}

t= 301.143 s

v= \frac{s}{t} \\s= v_{x}*t

s= 922.059 \frac{m}{s} * 301.143 s

s = 277671.77 m

4 0
3 years ago
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