A buffer solution contains 0.368 M hydrocyanic acid and 0.360 M potassium cyanide . If 0.0513 moles of sodium hydroxide are adde d to 225 mL of this buffer, what is the pH of the resulting solution
1 answer:
Solution :
Millimoles of hydrocyanic acid = 225 x 0.368
= 82.8
Millimoles of potassium cyanide = 225 x 0.360
= 81
Millimoles of sodium hydroxide = 51.3
Therefore,
pOH = pKb + log [salt - C / bas + C]
= 4.74 + log[82.8 - 51.3 / 81 + 51.3]
= 4.102
Therefore, pH = 9.05
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