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siniylev [52]
3 years ago
11

Compared to that of a plane on the ground, Earth’s gravitational pull on a plane 7 miles above Earth is approximately A) zero. B

) the same. C) half as much. D) twice as much.
Physics
2 answers:
NeTakaya3 years ago
7 0
I am proply right that it is B
Nezavi [6.7K]3 years ago
6 0
The correct answer is 

B) the same
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A. 24.89<br> B. 25.89<br> C. 17.74<br> D. 19.73
Veronika [31]

Answer: D

Explanation:

Just did it got an 100

5 0
2 years ago
As a marble rolls across the floor, it gradually slows to a stop due to friction. Which statement best describes the change in m
Olegator [25]

Answer:

I belive it would be "C"

Explanation:

If it was any of the other answers "B" it would instantly stop. "A" it would roll forever.

3 0
3 years ago
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of
motikmotik

Explanation:

It is given that, the force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed such that,

F\propto \dfrac{mgv^2}{r}

F=\dfrac{kmgv^2}{r}

mg is the weight of the car

r is the radius of the curve

v is the speed of the car

Case 1.

F = 640 pounds

Weight of the car, W = mg = 2600 pound

Radius of the curve, r = 650 ft

Speed of the car, v = 40 mph

640=\dfrac{k(2600)(40)^2}{650}

k = 0.1

Case 2.

Radius of the curve, r = 750 ft

Speed of the car, v = 30 mph

F=\dfrac{0.1\times 2600\times (30)^2}{750}

F = 312 N

Hence, this is the required solution.

6 0
2 years ago
How much energy is required to move an electron through a potential difference of
Tresset [83]
I think it’s going to be the 2nd one
3 0
2 years ago
An Ethernet cable is 4.00m long. The cable has a mass of 0.200kg . A transverse pulse is produced by plucking one end of the tau
Mashcka [7]

Based on the length of the Ethernet cable and the mass, the tension in the cable can be found to be 80 N.

<h3>How much tension is in the cable?</h3>

The tension in the cable can be found as:

= 4 x mass x length x frequency

Solving for the frequency is:

= 1 / (0.800 / 4)

= 1 / 0.20

= 5.0 Hz

The tension is therefore:

= 4 x 0.20 x 4.00 x 5

= 80N

Find out more on tension at brainly.com/question/14336853

#SPJ4

4 0
1 year ago
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