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Firdavs [7]
3 years ago
12

An electrolytic cell can be used to plate gold onto other metal surfaces. The plating reaction is: Au (aq) e- --> Au(s) Notic

e from the reaction that 1 mol e- plates out 1 mol Au(s). Use this stoichiometric relationship to determine how much time is required with an electrical current of 0.200 amp to plate out 0.400 g Au. The amp is a unit of electrical current equivalent to 1 C / s. (Hint: Recall that the charge of an electron is 1.60 x 10-19 C.)
Physics
1 answer:
Dmitriy789 [7]3 years ago
4 0

Answer:

Explanation:

Faraday’s constant can be used to convert the charge (Q) into moles of electrons (n). The charge is the current (I) multiplied by the time

Q = I × t = n × F

Where

Q is charge

I is current = 0.2A

t is time = ?

n is number of mole

F is Faraday constant = 96500C/s

Mass of Au = 0.4 g = 0.0004kg

Molar mass of Au = 197 g/mol

Malar mass = mass / mole

n = 0.4 / 197

n = 2.03× 10^-3 mol

n = 0.00203 mol

t = n × F / I

t = 0.00203 × 96500 / 0.2

t = 979.7 seconds

t = 16.32 minutes.

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Explanation:

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3 0
3 years ago
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2. What is the magnitude of the force a 1.5 C charge exerts on a 3.2 C charge
lesya [120]

The magnitude of the force is F=1.68×10 ^20  N

<u>Explanation:</u>

<u>Given data</u>

q1 =1.5  10 ^6 q2=3.2 10^6   r=1.5

<u>We have the formula</u>

By the coulomb's law

F= K. q1 ×q2 / r²

The K value is given by    

8.99  10^9 Nm²/ c²

substitute the values we get,

F= ( 8.99×  10^9 Nm²/ c²) ×(<u>1.5 ×10 ^6</u>)×(<u>3.2 ×10 ^6</u>)/ (1.6 m² )

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The magnitude of the force is F=1.68×10 ^20  N

4 0
3 years ago
Can someone please help!!
frosja888 [35]

Answer:

Weight needed to balance the bar is 8.5N

Explanation:

Given the weight of the bar is 8N

The length of the bar is 5m

The weight of the bar will be uniformly distributed over the entire span. We will consider this as a point load acting in the middle of span length, which is at a distance of 2.5m from both ends.

Now applying momentum equation about balanced load we get, (see attachment)

\sum m_i=0\\2(m)+8(1)-8(0.5)-7(3)=0\\2m+8-4-21=0\\2m-17=0\\2m=17\\m=\frac{17}{2}=8.5\\So,\ m=8.5N

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3 years ago
If red light hits a red filter, what kind of light comes through the filter?
Roman55 [17]
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8 0
3 years ago
In an oscillating LC circuit, the maximum charge on the capacitor is qm. Determine the charge on the capacitor, q, and the curre
Katarina [22]

Answer:

a. q = qm/√2 b. qm/√(2LC)

Explanation:

a. Charge on the capacitor

Let U₁ = energy in inductor and U₂ = energy in capacitor and U = total energy in circuit.

So, U₁ + U₂ = U.

Since the energy is shared equally between the capacitor and inductor, U₁= U₂,so

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U = (qm)²/2C where qm is the maximum charge on the capacitor.

Since U₂ = U/2,

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taking square-root of both sides, we have

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b. The current in the inductor

Since the energy in the capacitor equals the energy in the inductor,

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taking square-root of both sides, we have

I = q/√LC

substituting the value of q from above, we have

I = qm/√2 ÷ √LC

I = qm/√(2LC)

6 0
3 years ago
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