Answer:
0.014 kg
Explanation:
trust me its right i took the assessment and got 100%. :)
Answer:
(4) A = 3 A, A₂ = 11 A
(5) 7 A
Explanation:
(4)
From the diagram,
A = 3+6+2
A = 11 A
V = A₂R
A₂ = V/R₂............ Equation 1
Given: V = 12 V, R₂ = 4 Ω
Substitute these values into equation 1
A₂ = 12/4
A₂ = 3 A
(5) Applying,
V = IR'
I = V/R'............ Equation 1
Where V = Voltage, I = cuurent, R' = total resistance.
But,
1/R' = (1/3)+(1/4)
1/R' = (3+4)/12
1/R' = 7/12
R' = 12/7 Ω
Given: V = 12 V
Substitute these values into equation 1
I = 12/(12/7)
I = 7 A
Therefore
A = 7 A
Answer:
4009.21658986 Hz
Explanation:
v = Speed of sound in air = 348 m/s
L = Length of tube = 2.17 cm
Fundamental frequency for a tube where one end is closed and the other end open is given by
The fundamental frequency of the canal is 4009.21658986 Hz
Answer:
A) 5m/s
Explanation:
Momentum of ball in one direction=momentum of cannon in other direction
mv = mv
(10)(500)=(1000)v
5000=1000v
∴v=5m/s