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Yanka [14]
3 years ago
7

How much work do you do when you push a shopping cart with a force of 20 N for a distance of 5m?

Physics
1 answer:
KiRa [710]3 years ago
6 0

Answer:

A.100J

Explanation:

Given parameters:

Force on car = 20N

Distance  = 5m

Unknown:

Work done  = ?

Solution:

Work done is the product of force and distance;

  Work done  = force x distance;

Insert given parameters and solve;

        Work done  = 20 x 5  = 100J

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As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to
qwelly [4]

Answer:

2.4\cdot 10^{10}N

Explanation:

When an electric charge is immersed in an electric field, it experiences a force given by the equation

F=qE

where

q is the charge

E is the magnitude of the electric field

In this problem, we have:

q=+1.25\cdot 10^{-19}C is the charge on the small piece of lint

F=3.0\cdot 10^{-9}N is the force experienced by the  charge

Therefore, we can find the magnitude of the electric field by re-arranging the equation and solving for E:

E=\frac{F}{q}=\frac{3.0\cdot 10^{-9}}{1.25\cdot 10^{-19}}=2.4\cdot 10^{10}N

5 0
3 years ago
Which of the following best describes reflection?
Margarita [4]
B. Reflection is when waves bounce off a surface Ik this because I did it in 7th grade was my favorite unit to learn in school
4 0
3 years ago
Read 2 more answers
A carnival ride has a 2.0m radius and rotates once each .90s. Find the centripetal acceleration
Paraphin [41]
We know that centripetal acceleration is nothing but the ratio of the square of the tangential velocity to that of the radius vector.
a=v*v/r=ωωrr/r
=ωωr
=2πf2πfr
=2π2πr/TT
=97m/secsec
3 0
3 years ago
The electrical resistance of an element in a platinum resistance thermometer at 100°c, 0°c and room temperature are 75.00Ω, 63.0
Dominik [7]

Answer:

16.6 °C

Explanation:

From the question given above, the following data were obtained:

Temperature at upper fixed point (Tᵤ) = 100 °C

Resistance at upper fixed point (Rᵤ) = 75 Ω

Temperature at lower fixed point (Tₗ) = 0 °C

Resistance at lower fixed point (Rₗ) = 63.00Ω

Resistance at room temperature (R) = 64.992 Ω

Room temperature (T) =?

T – Tₗ / Tᵤ – Tₗ = R – Rₗ / Rᵤ – Rₗ

T – 0 / 100 – 0 = 64.992 – 63  / 75 – 63

T / 100 = 1.992 / 12

Cross multiply

T × 12 = 100 × 1.992

T × 12 = 199.2

Divide both side by 12

T = 199.2 / 12

T = 16.6 °C

Thus, the room temperature is 16.6 °C

6 0
3 years ago
One object (LaTeX: m_1m1) has a mass of 2 kg and moves with a speed of 9 m/s to the right. Another object (LaTeX: m_2m2) has a m
defon

Answer:

The correct answer is B

Explanation:

The moment of an object is the product of its mass by velocity, it is described by the equation

          p = mv

In this problem they give us the most body and speeds before and after the crash. We must define an environment with both bodies so that the forces during the crash have been internalized and the moment is preserved

         Δp = pf -p₀

         Δp = m v_{f} - m v₀

         Δp = 2 9 -2 1.5

         ΔP = 14.8 m/s

The correct answer is b

7 0
3 years ago
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