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Dafna1 [17]
2 years ago
12

Tungsten fits best into which category?

Chemistry
2 answers:
torisob [31]2 years ago
7 0
B. Element it is on the periodic table
nordsb [41]2 years ago
4 0

Answer:

B. Element

Explanation:

Tungsten is an chemical element

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Paul [167]
A million years old
Duhhhh
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How many grams are in 0.572 moles of glucose, C6H12O6
LUCKY_DIMON [66]

Answer:

103.00

Explanation:

1 mole of Glucose

6 C = 6 * 12 = 72 grams

12H = 12 * 1 = 12 grams

6O = 6 * 16 =96 grams

Total          = 180 grams

0.572 moles of Glucose

1 mol of glucose = 180 grams

0.572 mols of glucose = x

x = 0.572 * 180

x = 103.00 grams

6 0
3 years ago
What are the sources of petrochemicals
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Petrochemicals are chemical products derived from petroleum, although many of the same chemical compounds are also obtained from other fossil fuels such as coal and natural gas or from renewable sources such as corn, sugar cane, and other types of biomass.

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2 years ago
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The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
When methane, CH4, is combusted, it produces carbon dioxide, CO₂, according to the unbalanced equation: CH4 +0₂ - CO₂ + H₂O.
nevsk [136]

The balanced equation will be CH_4 + 2O_2 --- > CO_2 + 2H_2O

<h3>Stoichiometric problems</h3>

The balanced equation of the reaction would be as follows:

CH_4 + 2O_2 --- > CO_2 + 2H_2O

The mole ratio of methane to carbon dioxide is 1:1.

10 grams of methane will give 10/16 = 0.625 moles

0.625 moles of carbon dioxide would give 0.625 x 44.01 = 27.506 grams.

Thus, 10 grams of methane will produce approximately 27 grams of carbon dioxide stoichiometrically.

The reaction obeys the law of conservation of mass because the atoms of all the elements before and after the reaction are balanced.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

3 0
2 years ago
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