Girlllll idkkkkknim just tryna get pointtttt
Answer:
Option A.
2Na + 2H2O —> 2NaOH + H2
Explanation:
To know which option is correct, we shall do a head count of the number of atoms present on both side to see which of them is balanced. This is illustrated below below:
For Option A:
2Na + 2H2O —> 2NaOH + H2
Reactant >>>>>>> Product
2 Na >>>>>>>>>>> 2 Na
4 H >>>>>>>>>>>> 4 H
2 O >>>>>>>>>>>> 2 O
Thus, the above equation is balanced.
For Option B:
2Na + 2H2O —> NaOH + H2
Reactant >>>>>>> Product
2 Na >>>>>>>>>>> 1 Na
4 H >>>>>>>>>>>> 3 H
2 O >>>>>>>>>>>> 1 O
Thus, the above equation is not balanced.
For Option C:
2Na + H2O —> 2NaOH + H2
Reactant >>>>>>> Product
2 Na >>>>>>>>>>> 2 Na
2 H >>>>>>>>>>>> 4 H
1 O >>>>>>>>>>>> 2 O
Thus, the above equation is not balanced.
For Option D:
Na + 2H2O —> NaOH + 2H2
Reactant >>>>>>> Product
1 Na >>>>>>>>>>> 1 Na
4 H >>>>>>>>>>>> 5 H
2 O >>>>>>>>>>>> 1 O
Thus, the above equation is not balanced.
From the illustrations made above, only option A is balanced.
Molar mass Na = 23g/mol
46g = 456/2 = 2mol
1mol = 6.022*10^23 atoms
2mol = 2*6.022*10623
= 1.204*10^24 atoms
Answer:
Ok! I have four tips!
Explanation:
Create A Time Table.
Gather Information For Your Online Assignments Beforehand.
Make Notes As You Read The Course Materials.
Start Doing Your Online Assignment In Advance.
Answer:
Explanation:
First digit of the 2p^3 gives you value of n, in this case its = 2, So, n= 2
Second alphabet gives you the value of l,
l=0 =s
l=1 =p
l=3=d
l=4=f
since "p" is the alphabet in 2p^3, so in your case lt shoudlbe = 1 right?
ml= -l to +l , that is -1, 0, +1
Ms= +1/2 or -1/2 alaways remains same foe evrything.