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kykrilka [37]
2 years ago
5

Which theory proposed by Galileo is considered a “big mistake of his life”? What did the theory state, and why was it a “big mis

take”?
Physics
2 answers:
e-lub [12.9K]2 years ago
7 0
The erroneous theory of Galileo was that tides were a result of the earth's what he called the inconsistent revolution around the sun. He was right about the most important thing of the earth revolving around the sun but didn't realize that the moon (and sun) exert a gravitational pull on the earth's oceans and cause the diurnal tides to occur.
g100num [7]2 years ago
7 0

Answer:

The erroneous theory of Galileo for formation of tides.

Explanation:

As per Galileo, Earth's moment around sun results into formation of tides as he was trying to connect this with Copernicus Universe structure.

But this theory for explaining tide formation was wrong as he did not took Moon's gravitational force into consideration.

Later on this was proved that tides are the result of gravitational force between the Earth and the Moon.

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zhannawk [14.2K]

Answer:

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7 0
2 years ago
Calculate the force needed to bring a 1,019-kg car to rest from a speed of 29 m/s in a distance of 118 m
son4ous [18]
Acceleration = ▵v/▵t
Time = d/v
Fisrt calculate time : ( 118/29 ) = 4 seconds
Then calculate acceleration
A = 29/4 = 7.25 m/s²
Now the force.
Force = mass * acceleration.
F= 1,019 * 7.25
F= 7,387 N
8 0
2 years ago
An archer pulls her bowstring back 0.410 m by exerting a force that increases uniformly from zero to 270 N. How much work is don
Nitella [24]

Answer:

<em>110.7Joules</em>

Explanation:

<em>Work is said to be done when the force applied to a body cause the body to move through a distance.</em> Mathematically:

Work done = Force * Distance

Given the following

Force = 270 -0  = 270N

Distance moved = 0.410m

Required

The work done

Substitute the given parameters into the formula

Workdone = 270 * 0.41

Workdone = 110.7Joules

<em>Hence the work done in pulling the bow is 110.7Joules</em>

6 0
2 years ago
What provides the source of the earth’s magnetic field?
ololo11 [35]
<h2>Answer: the core of the earth</h2>

The explanation accepted by science until now, indicates that Earth's magnetic field is generated in the deepest of the terrestrial nucleus.

This is due to the movements of liquid metals in the core of the planet.

To explain it in more detail:

Right in the center of the Earth there is an internal core of solid iron at a very high temperature, this iron is as hot as the surface of the Sun, however, the pressure caused by the gravity force prevents it from becoming liquid. Around this inner core is the outer core, a layer of approximately 2000 km thick, composed of iron, nickel and small amounts of other metals in liquid state. Due to the lower pressure of the outer core, in relation to the inner core, the metal here is fluid (molten).

The differences in temperature, pressure and composition within the outer core cause convection currents in the molten metal, as the cold, dense matter sinks, and the warm, less dense matter rises. In addition, the Coriolis force, resulting from the spin of the Earth, also causes eddies in this mixture of molten metals.

This is how the movement of liquid iron inside the Earth generates electric currents, which in turn produce magnetic fields, and the spiral caused by the Coriolis force causes the magnetic fields to align in approximately the same direction, being this combined effect added to produce a vast magnetic field that envelops the entire planet.

This field extends from the terrestrial nucleus, progressively attenuating itself in outer space. However, it should be noted that unlike the field of a bar magnet, the Earth's magnetic field changes over time because it is actually generated by the movement of the iron alloys in the Earth's outer core, which causes the poles to move.

8 0
2 years ago
Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm sit
valina [46]
Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

The linear density:

\begin{gathered} \lambda=18\mu C\text{ /cm} \\  \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\  \\ \lambda=0.0018\text{ C/m} \end{gathered}

Point r = 3 cm = 3/100 m

r = 0.03 m

The electric field strength is calculated below

\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\  \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\  \\ E=719709237.468\text{ N/C} \\  \\ E=7.2\times10^8\text{ N/C} \\  \end{gathered}

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

8 0
1 year ago
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