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allochka39001 [22]
3 years ago
11

Blank have a definite shape and do not easily take the shape of their container

Physics
2 answers:
Fantom [35]3 years ago
7 0
Solids do no take to the shape of their containers, unlike liquids and gasses which do
Alja [10]3 years ago
5 0

Explanation:

An object whose particles are held by strong intermolecular forces of attraction is known as a solid substance.

In solids, particles have least kinetic energy and they can only vibrate at their position.

Therefore, solids have a definite shape and volume.

Hence, when we place a solid object in a container then it is unable to take the shape of container because its molecules are held strongly with each other.

Thus, they bond between its molecules cannot be broken down easily.

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8 0
3 years ago
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A student grabs a piece of paper and tears it from the middle. Which statement best explains the forces involved?
PolarNik [594]

Answer:

b. The normal force between the molecules of the paper is overcome by the contact force of the hands.

Explanation:

The paper molecules are held together by a weak bond. When the student holds the paper on both sides with the center of the paper in between, the student applies two equal forces in the opposite direction of the paper making the paper molecules weaken and separate.

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2 years ago
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Digiron [165]
Speed is the answer
4 0
2 years ago
) In the figure below, three charges K, L and M are placed at the corners of an equilateral triangle. If K and L are fixed, in w
abruzzese [7]

Answer:

B)

Explanation:

Negative (-) charge M will not move towards negative (-) charge K because, same charges will not attract each other in the given case

Negative (-) charge at the M tends to move towards positive (+) charge L in the direction of B) because opposite charges attract each other.

4 0
3 years ago
A uniformly charged, straight filament 5.10 m in length has a total positive charge of 2.00 µC. An uncharged cardboard cylinder
Ratling [72]

Answer:

70509.8039216 N/C

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = 2.00 µC

l = Length of filament = 5.1 m

r = Radius of cylinder = 10 cm

\lambda=\dfrac{q}{l}

Electric field is given by

E=\dfrac{2k\lambda}{r}\\\Rightarrow E=\dfrac{2\times 8.99\times 10^9\times \dfrac{2\times 10^{-6}}{5.1}}{10\times 10^{-2}}\\\Rightarrow E=70509.8039216\ N/C

The electric field at the surface of the cylinder is 70509.8039216 N/C

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3 years ago
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