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adelina 88 [10]
2 years ago
6

How many moles are in 4561 g of C3H7OH?

Chemistry
1 answer:
d1i1m1o1n [39]2 years ago
3 0

Answer: 76.017 moles

Explanation:

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If a train travels from San Antonio to El Paso at a speed of 90 mph, how far will it
Minchanka [31]

Answer:it have traveled a total of 315 miles

Explanation: 90 times three because 90 mph times 3 hours=270miles+ the 45 miles from the 30 min times 90 mph=45+ 270=315.

4 0
3 years ago
Fluorine (F) and bromine (Br) are in the same group on the periodic table. How do atoms of these elements compare when they form
stiks02 [169]

Answer:

they both gain one electron

Explanation:

they are both halogens and they each have one unpaired electron so that unpaired electron join together to make them form a bond

5 0
3 years ago
A molecule has the empirical formula C4H6O. If its molecular weight is determined to be about 212 g/mol, what is the most likely
krok68 [10]

Answer:

The molecular formula is C12H18O3

Explanation:

Step 1: Data given

The empirical formula is C4H6O

Molecular weight is 212 g/mol

atomic mass of C = 12 g/mol

atomic mass of H = 1 g/mol

atomic mass of O = 16 g/mol

Step 2: Calculate the molar mass of the empirical formula

Molar mass = 4* 12 + 6*1 +16

Molar mass = 70 g/mol

Step 3: Calculate the molecular formula

We have to multiply the empirical formula by n

n = the molecular weight of the empirical formula / the molecular weight of the molecular formula

n = 70 /212 ≈ 3

We have to multiply the empirical formula by 3

3*(C4H6O- = C12H18O3

The molecular formula is C12H18O3

3 0
3 years ago
Read 2 more answers
What term refers to rows of elements
qaws [65]
Period are going left to right across the periodic table
Groups are going up to down on the periodic table
3 0
2 years ago
Read 2 more answers
A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the
yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X  1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of  H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

For a detailed study of the empirical formula refer given link brainly.com/question/13058832.

#SPJ1.

5 0
1 year ago
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