Answer:
Answer : (1) :-
Volume of water filled in the pycnometer is given as = 9.9872 mL.
Mass of pycnometer when filled with water = 23.1148 g.
Mass of empty pycnometer = 13.1455 g.
So, mass of water = (23.1148 - 13.1455) g. = 9.9693 g.
We know that,
<em> Density = Mass / Volume = (9.9693 g.) / (9.9872 mL) = </em>0.998 g/mL.
<u>It is observed that the density of water is evaluated to be 0.998 g/mL. We know that, at 4℃ the density of water becomes maximum i.e. 1 g/mL. On the other hand the temperature at which the density of water is 0.998 g/mL is 0℃. Therefore, it can be concluded that the experiment was performed at a temperature of 0℃.</u>
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MAl₂(SO₄)₃·xH₂O:
(mAl×2) + (mS×3) + (mO×12) + (mH₂O×x)
(27×2)+(32×3)+(16×12)+(x×18) = 342 + 18x [g]
mAl₂: 27×2 = 54 [g]
54g ---------- 13,63%
342+18x ---- 100%
0,1363(342+18x) = 54
46,6146 + 2,4534x = 54
2,4534x = 7,3854
x ≈ 3
>>> Al₂(SO₄)₃·3H₂O <<<<
:)
Answer:
use google and use the first link
Explanation:
Coplorites I believe.
Hope this helps!
:)
