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Sliva [168]
3 years ago
6

If an element has a half life of one million years, how long will it take to be completely gone

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
3 0
It should be 2 million years
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Hydrogen bonds are formed between molecules when hydrogen is covalently bonded to an element that has a
stepan [7]

Answer:

choice 3

Explanation:

Hydrogen bonding occurs when a H is bonded to a highly electronegative atom like F. Towards the upper right corner, most atoms have high electronegativity and small atomic radii, according to periodic trends.

Please give thanks :)

7 0
3 years ago
Which formula represents copper(I) oxide?<br> (1) CuO (3) Cu2O<br> (2) CuO2 (4) Cu2O2
faust18 [17]
The answer is (3) Cu2O. Copper (I) has an oxidation state of +1 (that's what the "I" indicates). You can also think of this as copper (I) having a charge of +1. Oxygen has an oxidation state of -2 (that's just a rule you have to know), and you can think of it as oxygen having a charge of -2. You need oxidation numbers in a neutral compound to add up to 0 (or charges in a neutral compond to add up to 0), so you need two Cu to balance the O, which is Cu2O.
3 0
3 years ago
Read 2 more answers
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Nikolay [14]

Explanation:

Molar mass of KClO_{3} = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of O_{2} = 32.0 g

According to the equation, 2 moles of KClO_{3} reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of KClO_{3} will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of KClO_{3} gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of KClO_{3} as follows.

       \frac {96g}{245.2g} \times 2.72 g = 1.06 g of O_{2}


(b) Calculate the amount of oxygen given by 0.361 g of KClO_{3} as follows.

    \frac {96g}{245.2g} \times 0.361 g = 0.141 g of O_{2}


c) Calculate the amount of oxygen given by 83.6 kg KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 83.6 g = 32.731 kg of O_{2}

Convert kg into grams as follows.

    \frac{32.731 kg}{1 kg} \times 1000 g = 32731 g of O_{2}


(d) Calculate the amount of oxygen given by 22.5 mg of KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 22.5 mg = 8.79 mg

Convert mg into grams as follows.

  \frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g of O_{2}

8 0
3 years ago
If you had excess aluminum, how many moles of aluminum chloride could be produced from 28.0 g of chlorine gas, Cl2?
Mice21 [21]

Answer:

Yes chemistry. Try to add then multiply the top. Get the moles and you will find it.

Explanation:

Try to add then multiply the moles in the equation

6 0
3 years ago
You apply 100.0 of force to a machine. The machine applies 20.0 N of force to the load. What is the mechanical advantage of the
rjkz [21]
MA= output force/input force
MA= 100N/20N
MA= 50
5 0
3 years ago
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