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Anna35 [415]
3 years ago
9

An air track car with a mass of 0.55 kg and velocity of 5.8 m/s to the right collides and couples with a 0.45 kg car moving to t

he left with a velocity of 3.9 m/s. What is the combined velocity of the cars just after the collision?
Physics
1 answer:
SVEN [57.7K]3 years ago
5 0

Explanation:

Given:

m1 = 0.55 kg

m2 = 0.45 kg

vi1 = +5.8 m/a

vi2 = -3.9 m/a

Solve for V

m1vi1 + m2vi2 = (m1 + m2)V

(0.55 kg)(+5.8 m/s) + (0.45 kg)(-3.9 m/s) = (0.55 + 0.45)V

V = +1.46 m/a

This means that the combined mass after the collision is moving to the right at 1.46 m/s

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Answer:

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Explanation:

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Converting days to seconds:

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w = 2π / 2,194,560 = 2.863x10^-6 rad/s

Now, the innitial angular momentum is:

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L = Iω = 2.863x10^-6 * 1.94x10^17 M

L = 5.55x10^11 m²/s * M = final angular momentum

Now the  final I = 2/5Mr²

Final I = 2/5 * (6.37x10^6)² * M  = 1.62x10^13m² * M

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