No.
Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a random error has been minimized or even eliminated.
<h3>What is a random error?</h3>
Random error is defined as the deviation of the total error from its mean value due to chance.
Random errors can result from the instrument not being precise or from mistakes by the researcher.
Random errors can be minimized by taking multiple readings and averaging the results.
Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a ransom error has been minimized.
Learn more about random errors at: brainly.com/question/22041172
Answer:
U = initial velocity, t = time taken, s = distance covered. Deceleration Formula is used to calculate the deceleration of the given body in motion.
Up until the moment the box starts to slip, the static friction is maximized with magnitude <em>f</em>, so that by Newton's second law,
• the net force acting on the box parallel to the ramp is
∑ <em>F</em> = <em>mg</em> sin(<em>α</em>) - <em>f</em> = 0
where <em>mg</em> sin(<em>α</em>) is the magnitude of the parallel component of the box's weight; and
• the net force acting perpendicular to the ramp is
∑ <em>F</em> = <em>n</em> - <em>mg</em> cos(<em>α</em>) = 0
where <em>n</em> is the magnitude of the normal force and <em>mg</em> cos(<em>α</em>) is the magnitude of the perpendicular component of weight.
From the second equation we have
<em>n</em> = <em>mg</em> cos(<em>α</em>)
and <em>f</em> = <em>µn</em> = <em>µmg</em> cos(<em>α</em>), where <em>µ</em> is the coefficient of static friction. Substituting these into the first equation gives us
<em>mg</em> sin(<em>α</em>) = <em>µmg</em> cos(<em>α</em>) ==> <em>µ</em> = tan(<em>α</em>) ==> <em>α</em> = arctan(0.35) ≈ 19.3°
Answer:
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Answer:
because it has a force exerted in the opposite direction
Explanation: