Sheila eats an energy bar right before she goes on a run. What energy changes will occur in sheila as she runs after eating?

2 answers:

8 0

The energy bar eaten by Sheila has chemical energy locked up inside it. This chemical energy is converted to mechanical energy in form of potential and kinetic energy and this in turn is converted to heat energy as the run progresses. Thus, the energy changes are: chemical energy to mechanical energy [kinetic and potential] and finally to heat energy.

lana66690 [7]3 years ago

8 0

Answer;

The chemical energy in food is converted to potential energy stored in the body which is then converted to mechanical and kinetic energy, as a result of motion while running then to heat energy.

Explanation;

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lana66690 [7]

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Derek and Diane race each other on bicycles. Derek starts 4 seconds before Diane. He goes at a steady speed of 6 m/s. Diane star

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a. $x(t) = vt' = v(t+4) = 6(t+4) [m]$

Let's call:

$t$ the time calculated from the moment Diane starts her motion and $t'$ the time calculated from the moment Derek starts his motion. Derek starts his motion 4 seconds before Diane: this means that has an "advantage" of 4 seconds, so we can write

$t'=t+4$

Then:

$v=6 m/s$ is the uniform speed of Derek

Derek is moving in a uniform motion, so Derek's position will be given by (assuming that the starting position is zero):

$x(t) = vt' = v(t+4) = 6(t+4) [m]$

We see that this is correct: in fact, when t=0 (instant when Diane starts her motion), Derek has already travelled for

$x(t=0)=v(0+4)=6 (4)=24 m$

b. $x'(t)= \frac{1}{2}at^2 =\frac{1}{2}(2)t^2=t^2 [m]$

t is the time calculated from the moment Diane starts her motion. Diane is moving by accelerated motion, with constant acceleration $a=2 m/s^2$ and initial velocity $v_0=0$ , so its position at time t is given by the law of uniform accelerated motion: