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Likurg_2 [28]
3 years ago
10

The difference between experimental technique and procedure

Physics
1 answer:
kaheart [24]3 years ago
4 0
A procedure is all the steps used to do an experiment in order. 
<span>the experiment is when you test your hypothesis and is designed to answer your question. </span>
<span>the procedure is all the steps of the experiment.</span>
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On level ground a shell is fired with an initial velocity of 49.0 m/s at 70.0 โ above the horizontal and feels no appreciable ai
xenn [34]

Answer:

Horizontal component = 16.8 m/s

Vertical component = 46.0 m/s

Explanation:

If we denote the initial velocity by <em>v</em> and the angle above the horizontal by <em>θ</em>,

the horizontal component of this initial velocity is given by

v_x = v\cos \theta

v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}

The vertical component is given by

v_y = v\sin\theta

v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}

3 0
2 years ago
Please tell me why the answer is zero
Oduvanchick [21]

This question is checking to see whether you understand the meaning
of "displacement".

Displacement is a vector: 

-- Its magnitude (size) is the distance between the start-point and
the end-point, no matter what route might have been followed along
the way.

-- Its direction is the direction from the start-point to the end-point.

Talking about the Earth's orbit around the sun, we can forget about
the direction of the displacement, and just talk about its magnitude
(size).

If we pretend that the sun is not moving and dragging the whole
solar system along with it, then what do we see the Earth doing
in one year ? 
We mark the place where the Earth is at the stroke of midnight
on New Year's Eve.  Then we watch it as it swings around through
this gigantic orbit, all the way around the sun, and in a year, it's back
to the same point that we marked ! 

So what's the magnitude of the displacement in exactly one year ?
It's the distance between the start-point and the end-point.  But the
Earth came back to the same place it started from, so there's no
separation at all between the start-point and the end-point. 
The Earth covered a huge distance in that year, but the displacement
is zero.

5 0
2 years ago
Read 2 more answers
Coil the wire around the nail. Connect one end of the wire to the positive battery terminal. Connect the other end of the wire t
Ostrovityanka [42]

A).  No.  In fact, the longer you leave things hooked up like this, the weaker the battery becomes.

<em>B).  Yes !  </em>As long as everything stays hooked up like this, the nail is a magnet. (Until the battery finally dies of exhaustion.)

C).  No.

D).  I don't think so.  Never heard of this one.

5 0
3 years ago
Just number 9 I need help !!!!
Deffense [45]
Magnesium is in group 2 while sulfur is in group 6.

the group number determines the number of valence electrons.

Metals gives lose electrons (mg)
Non Metals gain electrons (s)

answer: Magnesium gives 2 electrons to sulfur.

Mg is now 2.8
Sulfur is 2.8.8

cuz ionic bonding
8 0
3 years ago
A viscous liquid of constant density 500 kg/m3 and viscosity 10 Pa s falls down with constant velocity due to gravity in a long
Alekssandra [29.7K]

Answer:

\tau=2452.5 N/m^2

Explanation:

given:

density \rho=500kg/m^3

viscosity \mu= 10 Pa-s

diameter of tube= 2 m

and L be length

since gravity is the only force shear force will balance it

so we can write

mg= \tau\times A

A=  \rho\times\frac{\pi}{4} d^2\times L

m=  \rho\times\frac{\pi}{4} d^2\times L

therefore

\rho\times\frac{\pi}{4} d^2\times Lg= \tau\times{\pi} d\times L

putting values we get

\ 500\times\frac{\pi}{4} 2^2\times g= \tau\times{\pi}\times 2

calculating we get \tau=2452.5 N/m^2

6 0
3 years ago
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