Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 50.4 m/s
Final speed of the ball, v = -37 m/s (As it returns)
(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :
![J=m(v-u)](https://tex.z-dn.net/?f=J%3Dm%28v-u%29)
J = -5.24 kg-m/s
(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.
![W=\dfrac{1}{2}m(v^2-u^2)](https://tex.z-dn.net/?f=W%3D%5Cdfrac%7B1%7D%7B2%7Dm%28v%5E2-u%5E2%29)
![W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)](https://tex.z-dn.net/?f=W%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.06%5Ctimes%20%28%28-37%29%5E2-%2850.4%29%5E2%29)
W = -35.1348 Joules
Hence, this is the required solution.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
Answer:
45.88297 m
Violet
Explanation:
x = Gap between holes = 5.9 mm
= Wavelength = 527 nm
D = Diameter of eye = 5 mm
L= Distance of observer from holes
From Rayleigh criteria we have the relation
![\frac{x}{L}=1.22\frac{\lambda}{D}\\\Rightarrow L=\frac{xD}{1.22\lambda}\\\Rightarrow L=\frac{5.9\times 10^{-3}\times 5\times 10^{-3}}{1.22\times 527\times 10^{-9}}\\\Rightarrow L=45.88297\ m](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7BL%7D%3D1.22%5Cfrac%7B%5Clambda%7D%7BD%7D%5C%5C%5CRightarrow%20L%3D%5Cfrac%7BxD%7D%7B1.22%5Clambda%7D%5C%5C%5CRightarrow%20L%3D%5Cfrac%7B5.9%5Ctimes%2010%5E%7B-3%7D%5Ctimes%205%5Ctimes%2010%5E%7B-3%7D%7D%7B1.22%5Ctimes%20527%5Ctimes%2010%5E%7B-9%7D%7D%5C%5C%5CRightarrow%20L%3D45.88297%5C%20m)
A person could be 45.88297 m from the tile and still resolve the holes
Resolving them better means increasing the distance between the observer and the holes. It can be seen here that the distance is inversely proportional to the wavelength. Violet has a lower wavelength than red so, violet light would resolve the holes better.
Answer:
<em><u>option</u></em><em><u> (</u></em><em><u>C)</u></em><em><u> </u></em><em><u>is </u></em><em><u>right</u></em><em><u> answer</u></em>
Explanation:
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