Explanation:
1.
We use the equation
h = , where
h is the height traveled,
g is the acceleration due to gravity and
t is the time taken to reach height h.
We can now calculate t to be
= 0.495 s
Let v be the initial velocity of the player.
The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.
v = 9.81 m/s^2 x 0.495 s = 4.85 m/s
2.
The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is
4.85 m/s / 0.3 s = 16.2 m/s^2
Answer:
Work done, W = 0.0219 J
Explanation:
Given that,
Force constant of the spring, k = 290 N/m
Compression in the spring, x = 12.3 mm = 0.0123 m
We need to find the work done to compress a spring. The work done in this way is given by :
W = 0.0219 J
So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.
5.5 s
Explanation:
The time it takes for the ball to reach its maximum height can be calculated using
since at the top of its trajectory. Plugging in the numbers,
Explanation:
The given data is as follows.
q = -25.0 kJ, Pressure (P) = 1.50 atm
= (12 - 6) L = 6 L
Therefore, product of pressure and change in volume will be as follows.
= 7.5 L atm
=
= 759.75 J
Now, we will calculate the change in internal energy as follows.
=
= -25000 kJ + 759.75 J
= 24240.25 J
or, = 24.240 kJ (as 1 kJ = 1000 J)
Thus, we can conclude that the change in internal energy () for a system is 24.240 kJ.