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Nataliya [291]
3 years ago
8

Basketball player Darrell Griffith is on record as

Physics
1 answer:
Gre4nikov [31]3 years ago
5 0

Explanation:

1.

We use the equation

h = \frac{gt^2}{2}, where

h is the height traveled,

g is the acceleration due to gravity and

t is the time taken to reach height h.

We can now calculate t to be

\sqrt{\frac{2*1.2 m}{9.81 m/s^2} }

= 0.495 s

Let v be the initial velocity of the player.

The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.

v = 9.81 m/s^2 x 0.495 s = 4.85 m/s

2.

The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is

4.85 m/s / 0.3 s = 16.2 m/s^2

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The work done to compress a spring with a force constant of 290.0 N/m a total of 12.3 mm is: a) 3.57 J b) 1.78 J c) 0.0219 J d)
iren2701 [21]

Answer:

Work done, W = 0.0219 J

Explanation:

Given that,

Force constant of the spring, k = 290 N/m

Compression in the spring, x = 12.3 mm = 0.0123 m

We need to find the work done to compress a spring. The work done in this way is given by :

W=\dfrac{1}{2}kx^2

W=\dfrac{1}{2}\times 290\times (0.0123)^2

W = 0.0219 J

So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.

7 0
4 years ago
Based on the thermodynamic functions of enthalpy and entropy, can an unfavorable reaction that has a positive δg at rt be made f
Over [174]
I believe that the answer to the question provided above is yes, an unfavorable reaction that has a positive δg at rt be made favorable by increasing the reaction temperature.
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
7 0
4 years ago
All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will
VikaD [51]

5.5 s

Explanation:

The time it takes for the ball to reach its maximum height can be calculated using

v_y = v_{0y} - gt \Rightarrow t = \dfrac{v_{0y}}{g}

since v_y = 0 at the top of its trajectory. Plugging in the numbers,

t = \dfrac{(54\:\text{m/s})}{(9.8\:\text{m/s}^2)} = 5.5\:\text{s}

8 0
3 years ago
Calculate the change in internal energy (ΔE) for a system that is giving off 25.0 kJ of heat and is changing from 12.00 L to 6.0
Alexxandr [17]

Explanation:

The given data is as follows.

         q = -25.0 kJ,     Pressure (P) = 1.50 atm

   \Delta V = (12 - 6) L = 6 L

Therefore, product of pressure and change in volume will be as follows.

             P \Delta V = 1.50 atm \times 6 L

                                = 7.5 L atm

                                = 7.5 \times 101.3

                                = 759.75 J

Now, we will calculate the change in internal energy as follows.

                   \Delta E = q + w

                                = q + P \Delta V

                                = -25000 kJ + 759.75 J

                                 = 24240.25 J

or,                              = 24.240 kJ      (as 1 kJ = 1000 J)

Thus, we can conclude that the change in internal energy (\Delta E) for a system is 24.240 kJ.

7 0
4 years ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)
3 0
3 years ago
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