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Kobotan [32]
3 years ago
6

Nncncncncncncncaaaaaaa

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

nncncncncncncncnccnaaaaa

kirill [66]3 years ago
5 0
I agree hope this helps
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What is the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol)?
NemiM [27]

the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g

The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn

3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2

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m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3

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They are 1.204×10^24 atoms of hydrogen present in 18 grams of water. In order to calculate this,it is necessary to compute the number of hydrogen moles present in the sample.

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What is a scientific word for baking soda​
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Hope this helped

Brainliest is appreciated

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