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storchak [24]
3 years ago
13

Which Of The Following Would Represent An Increase In Entropy

Chemistry
2 answers:
bagirrra123 [75]3 years ago
8 0


I would say C. Since the material is getting warmer, the atoms and molecules will start to move fasten and then also create more "messiness" (which is entropy with a less-nice word)

lyudmila [28]3 years ago
6 0

Answer:

C. Thawing - APEX

Explanation:

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Liquid nitrogen is cold and can be used to cool objects to -196°C. If you put the bottle of warm air in liquid nitrogen at this
shtirl [24]

Answer:

It will boil.

Literally, every liquid has a boiling point, unless it chemically decomposes before it gets to that point (which liquid nitrogen certainly doesn't). At normal atmospheric pressure, it can be 'heated' to -196 C. At that point, any heat you put into it will go into boiling liquid nitrogen into nitrogen gas. At higher pressures, the same thing will happen at a higher temperature. Once all the liquid is boiled, the gas will continue to rise in temperature as long as heat is being added.

Explanation:

8 0
2 years ago
Convert the following to number of moles: 4.03 x 10^21 molecules present in AgNO3
castortr0y [4]
Moles = 4.03 x 10^21
             ------------------------
                6.02 x 10^23
 
           =      6.69 x 10^-3 moles.
Hope this helps!


6 0
3 years ago
A plastic bin is found to hold 3.1x10^24 molecules of water.
motikmotik

Answer:

\boxed {\boxed {\sf 5.1 \ mol \ H_2O}}

Explanation:

To convert from representative particles to moles, Avogadro's Number: 6.02*10²³, which tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance.

We can use it in a ratio.

\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}

Multiply by the given number of molecules.

3.1*10^{24} \ molecules \ H_2O*\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}

Flip the ratio so the molecules of water cancel out.

3.1*10^{24} \ molecules \ H_2O*\frac {1 \ mol \ H_2O}{6.02*10^{23} \ molecules \ H_2O}

3.1*10^{24} *\frac {1 \ mol \ H_2O}{6.02*10^{23} }

\frac {3.1*10^{24} \ mol \ H_2O}{6.02*10^{23} }

Divide.

5.14950166113 \ mol \ H_2O

The original number of molecules has 2 significant figures: 3 and 1, so our answer must have the same. For the number we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.

5.1 \ mol \ H_2O

There are about 5.1 moles of water in 3.1*10²⁴ molecules of water.

5 0
3 years ago
Explain why the gamma rays do not bend.
Natalka [10]
They are electrically neutral, they are not deflected by magnetic fields
6 0
3 years ago
An iron block of mass 18 kg is heated from 285 K to 318 K. If 267.3 kJ is required, what is the specific heat of iron? A. 450.00
valkas [14]

Answer:

  • <u>Option A. 450.00</u>

Explanation:

<u>1) Data:</u>

a) m = 18 kg

b) T₁ = 285 K

c) T₂ = 318 K

d) Q = 267.3 kJ

e) S = ?

<u>2) Principles and equations</u>

The specific heat of a substance is the amount of heat energy absorbed to increase the temperature of certain amount (gram, kg, or moles, depending on the definition or units) of the substance in 1 ° C or 1 K.

The mathematical relation between the specific heat and the heat energy absorbed is:

  • Q = m × S × ΔT

Where,

  • Q is the heat absorbed,
  • S is the specific heat, and
  • ΔT is the temperature increase (T₂ - T₁)

<u>3) Solution:</u>

<u>a) Substitute the data into the equation:</u>

  • 267.3 kJ = 18 kg × S × (318 K - 285 K)

<u>b) Solve for S and compute:</u>

  • S = 267.3 kJ / (18 kg × 33 K) = 0.45 kJ / (Kg . K)

The options have not units, but I notice that the first answer is 1,000 times the answer I obtained, so I will make a conversion of units.

<u>c) Convert to J /( kg . k):</u>

  • 0.45 kJ / (Kg . K) × 1,000 J / kJ = 450 J / (kg . K)

Now we can see that the option A is is the answer, assuming the units.

6 0
4 years ago
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