AN element is composed from atoms with the same number of protons,
A compound contain two or more different elements
Answer:
a) 5.4 * 10^-4 moles
b) 8.2 moles
c) 0.26 moles
d) 20.76 moles
Explanation:
a)Since 1 mole of a substance has 6.02 * 10^23 atoms
x moles is present in 3.25 x 1020 atoms of lead
3.25 x 1020 atoms of lead/6.02 * 10^23 atoms = 5.4 * 10^-4 moles
b) Since 1 mole of a substance has 6.02 * 10^23 molecules
x moles is present in 4.96 x 1024 molecules of glucose
x = 4.96 x 1024 molecules of glucose/6.02 * 10^23 molecules = 8.2 moles
c) Since 1 mole of a substance has 6.02 * 10^23 formula units
x moles is present in 1.56 x 1023 formula units of sodium hydroxide
x = 1.56 x 1023 formula units /6.02 * 10^23 = 0.26 moles
d) Since 1 mole of a substance has 6.02 * 10^23 ions
x moles is present in 1.25 x 1025 copper(ll) ions
x = 1.25 x 1025 copper(ll) ions/6.02 * 10^23 ions = 20.76 moles
Neon does not need to bond.
An atom will form a bond because it wants to have the noble gas configuration. Atoms that have the noble gas configuration have a full outer shell of electrons. Neon is in period 2 of the periodic table meaning it's outer shell holds a maximum of eight electrons. The electronic configuration of neon is 
or simply 2,8. The second energy level is full in neon, which is a stable configuration. Because neon has a full and stable outer shell, it does not need to bond .
Answer:
158.875
Explanation:
not 100 percent sure let me know if its correct or not
The molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.
<h3>What is Ksp?</h3>
The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃ Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³
AuCl₃(aq) ⇄ Au³⁺(aq) + 3Cl⁻(aq)
Let the solubility of the AuCl₃ in 0.013m solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ion and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 litre then the concentration of chloride ions in MgCl₂ is 2(0.010) = 0.020M.
So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.020.
Value of Ksp for AuCl₃ = 3.2 × 10⁻²⁵
On putting all values on the Ksp equation, we get
Ksp = (x)(3x + 0.020)³
Value of 3x is negligible as compared to the 0.020, so the equation becomes
3.2 × 10⁻²⁵ = (x)(0.020)³
x = 3.2×10⁻²⁵ / (0.020)³
x = 4 ×10⁻²⁰M
Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.
To know more about molar solubility, visit the below link:
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