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notsponge [240]
2 years ago
7

Solve the following problem and select the correct answer: (4.5 x103)(3.5 x102)

Chemistry
1 answer:
oee [108]2 years ago
7 0

Answer:

D: 1.6 x 10^6

Explanation:

(4.5 x103)(3.5 x102

Multiply

4.5 x 3.5 = 15.75

Now add 10^3 + 10^2 because we are finding the product of this.

10^3 + 10^2 = 10^5

Use sig figs

15.75 rounded to the whole number is 16.

A scientific notation always has to only have the tenths place only.

Change 16 to 1. 6

Then change 10^5 to 10^6

And your final answer would be 1.6 x 10^6.

Hope I helped!

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A(g) + 2B(g) → C(g) + D(g)
WITCHER [35]

Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

       A(g) + 2 B(g) ⇄ C(g) + D(g)

I       1.00     1.00        0        0

C       -x        -2x        +x       +x

E    1.00-x  1.00-2x     x         x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

6 0
3 years ago
What is the chemical formula for salt?
Hoochie [10]
In terms of the most common type of salt, sodium chloride, NaCl is the chemical formula of this salt,
3 0
3 years ago
How many moles are in 2.5L of 1.75 M Na2CO3
mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M Na_2CO_3

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

Molarity of solution = 1.75 M

Volume of solution = 2.5 L  

Putting values in equation , we get:

1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol

6 0
3 years ago
0.0075 mole of calcium trioxocarbonate(IV) is
KatRina [158]

Answer:

0.0075÷0.015=0.5 not so sure lol

4 0
3 years ago
If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density
ankoles [38]

Answer:

The length of the wire = 352.66 feet.

Explanation:

A copper refinery produces a copper ingot weighing 150 lb. If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density of copper is 8.94 g/cm3. (Assume that the wire is a cylinder whose volume is V = πr2h, where r is the radius and h is its height or length.)

Step 1: Convert lb to kg

150 lb = 68.0389 kg

Step 2: Calculate volume of copper

Volume = mass / density

Volume = 68038.9 grams / 8.94 g/cm³

Volume = 7610.6 cm³ Cu

Step 3: Calculate length of wire

The diameter of the wire is 9.50 mm, so the radius is half of that (4.75 mm), or 0.475 cm.

The total "volume" of the wire is πr²h = (π)*(0.475 cm)²(h) = 0.708h = 7610 cm^3

7610 = 0.708h

h = 10749 cm = length of wire

The length of the wire = 352.66 feet.

7 0
3 years ago
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