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mash [69]
3 years ago
13

What percent of 60 is 15

Mathematics
2 answers:
Natali5045456 [20]3 years ago
6 0
The question as an equation is 60p = 15, where p is the percentage you are solving for. divide both sides by 60 to get this as a fraction. Then simplify, and turn this into a percentage. 60p = 15 => p = 15/60 = 1/4 = 25/100 = 25%.

25%
Pie3 years ago
3 0
15/60<span> = x/100.</span>
cross multiply: 60x = 1500.
<span>now, divide both sides by 60 to isolate the variable x.</span>
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34 + 2 ⋅ 5 = ____. (Input only whole numbers.) PLZZZ help asp
Gwar [14]
PEMDAS order refers to parentheses, exponents, multiplication, division, addition, and subtraction. So, 2*5=10 and 34+10=44.
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A bouquet contains 6 roses and 9 daisies. This represents 75% of the flowers in the bouquet. How many total flowers are in the b
notka56 [123]

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20 total flowers

Step-by-step explanation:

9+6=15.

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Work out the value of 5x-2y when x=-2 and y=-3
max2010maxim [7]
I guess this how it would go
<span><span><span>(5)</span><span>(<span>−2</span>)</span></span>−<span><span>(2)</span><span>(<span>−3</span>)</span></span></span>

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3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

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x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
The graph of f(x)=√x Is shifted four units up and five units to the right. What is the equation of the resulting graph?
RoseWind [281]

A vertical shift adds/subtracts a constant to/from every y-coordinate while leaving the x-coordinate unchanged. A horizontal shift adds/subtracts a constant to/from every x-coordinate while leaving the y-coordinate unchanged. Vertical and horizontal shifts can be combined into one expression.

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the 3rd option is the correct one

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