Answer:
<em>The actual dimensions of the classroom are 50 cm x 70 cm</em>
Explanation:
<u>Scaling
</u>
When we need to represent real-world dimensions into small spaces, we use scaling. Distance scaling tells us what is the equivalence between the real units and the scaled units. In this case, we are told that 10 cm is equivalent to 1 meter. As 1 meter is 100 cm, it means that the scale is 100/10=10. Thus, each centimeter in the paper is equivalent to 10 cm in the real distance.
The classroom is 5 cm x 7 centimeters. Scaling back to the real values, the classroom has measures of 50 cm x 70 cm.
D would be correct.
Have a merry Christmas!
Answer:
23L
Explanation:
Given that:
Initial volume of water = 30mL
Final volume of water after an object was placed on it = 53mL
The volume object added which resulted in a rise to 5mL will be :
Final Volume of object - Initial volume of object
53 mL - 30mL = 23mL
Hence, volume of object added is 23 mL
Answer: d = 4750n/3.1+95n
Explanation:
Using the principle of moment to solve the question.
Sum of clockwise moments = sum of anti clockwise moments
Since there are n identical coins with mass 3.1g placed at point 0cm, 1 coin will have mass of 3.1/n grams
Taking moment about the pivot,
Mass 3.1/n grams will move anti-clockwisely while the mass 95g will move in the clockwise direction.
Since its a meter rule (100cm) the distance from the center mass(95g) to the pivot will be 50-d (check attachment for diagram).
To get 'd'
We have 3.1/n × d = 95 × (50-d)
3.1d/n = 4750-95d
3.1d = 4750n-95dn
3.1d+95dn=4750n
d(3.1+95n) = 4750n
d = 4750n/3.1+95n
